X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Mon, 05 Mar 2012 21:25:52 -0500 Message-ID: X-Original-Return-Path: Received: from mail-tul01m020-f180.google.com ([209.85.214.180] verified) by logan.com (CommuniGate Pro SMTP 5.4.4) with ESMTPS id 5429822 for lml@lancaironline.net; Mon, 05 Mar 2012 21:02:01 -0500 Received-SPF: pass receiver=logan.com; client-ip=209.85.214.180; envelope-from=jeffreyb.peterson@gmail.com Received: by obbwd18 with SMTP id wd18so4969142obb.25 for ; Mon, 05 Mar 2012 18:01:23 -0800 (PST) X-Original-Return-Path: Received-SPF: pass (google.com: domain of jeffreyb.peterson@gmail.com designates 10.60.12.231 as permitted sender) client-ip=10.60.12.231; Authentication-Results: mr.google.com; spf=pass (google.com: domain of jeffreyb.peterson@gmail.com designates 10.60.12.231 as permitted sender) smtp.mail=jeffreyb.peterson@gmail.com; dkim=pass header.i=jeffreyb.peterson@gmail.com Received: from mr.google.com ([10.60.12.231]) by 10.60.12.231 with SMTP id b7mr9077789oec.38.1330999283507 (num_hops = 1); Mon, 05 Mar 2012 18:01:23 -0800 (PST) MIME-Version: 1.0 Received: by 10.60.12.231 with SMTP id b7mr8007147oec.38.1330999283422; Mon, 05 Mar 2012 18:01:23 -0800 (PST) Received: by 10.182.33.166 with HTTP; Mon, 5 Mar 2012 18:01:23 -0800 (PST) Reply-To: jbp@cmu.edu X-Original-Date: Mon, 5 Mar 2012 21:01:23 -0500 X-Original-Message-ID: Subject: Re: LED light pipe tail light. From: Jeff Peterson X-Original-To: Lancair mail list X-Original-Cc: lancair1@bellsouth.net Content-Type: multipart/alternative; boundary=e89a8f83a47b7c178904ba896bcb --e89a8f83a47b7c178904ba896bcb Content-Type: text/plain; charset=ISO-8859-1 Does this meet the angular spread requirements for the FAA? I forget the particulars, but the white light pattern has to be seen across a broad swath to the rear and sides of the aircraft, as I recall. Douglas W. Johnson MD, FACR -------- Douglas, My calculations indicate that the system meets the minimum intensity requirements but I have not measured this to confirm the calculations. Here is the calculation.... The FAA requires at least 20 candela for the azimuth range 110 degrees to 250 degrees. (FAR 23.1391) The LED I used, LZ4-40CW00 ($15.20 at Mouser), uses 14 V, drawing 700 mA and puts out 680 lumens. 1 Candela = 1 Lumen/Steradian The aft-facing hemisphere has 2 pi steradians, so assuming the lightpipe transmits about 75% of the light the average brightness is 0.75 x 680 / (2 pi) = 81 candela I sanded the output end of the lightpipe flat, which should make the source approximately "lambertian", which means the amount of light you see at each angle is given just by the projected area of the sanded end that you see. This means the intensity pattern is an approximate cosine function of the azimuth, peaking in the aft direction. At 180 degrees azimuth the flux is higher than the 81 candela average, by a factor close to pi/2 so the peak intensity is around 127 candela. At 110 degrees (and 250) measured from the nose, the intensity is reduced to 127 x cosine (70 degrees) = 43 candela. This is more than twice the 20 candela requirement so yes, the LED/light pipe is bright enough. If I recall the old Whelen aft-facing white light uses 2 amps, so it is impressive that a little LED drawing 700ma can match it. -- Jeff Peterson --e89a8f83a47b7c178904ba896bcb Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Does this meet the angul= ar spread requirements for the FAA? I forget the particulars, but the white= light pattern has to be seen across a broad swath to the rear and sides of= the aircraft, as I recall.

Douglas W. Johnson MD, FACR

--------
Douglas,

My calculations indicate that the s= ystem meets the minimum intensity
requirements but I have not
measured this to confirm the calculations. =A0

Here is the= calculation....

The FAA req= uires at least 20 candela for the azimuth range 110 degrees to 250 degrees.=
(FAR 23.1391)
The LED I used, LZ4-40CW00 ($15.20<= /font>=A0 at Mouser),=A0
uses 14 V, drawing 700 mA and puts out 680 lumens.

1 Candela =3D 1 L= umen/Steradian

The aft-facing hemisphere has = 2 pi steradians, so assuming the lightpipe transmits about 75%
of the light the average brightness is 0.75 x 680 / (2 pi) = =3D 81 candela


I sanded the output end of the ligh= tpipe flat, which should make the source =A0approximately "lambertian&= quot;, which means the amount of light you see at each angle is given just = by the projected
area of the sanded end that you see. =A0This means the = intensity pattern is an approximate cosine function of the azimuth, peaking= in the aft direction.

At 180 degr= ees azimuth the flux is higher than the 81 candela average, by a factor clo= se to pi/2 so the peak intensity is=A0arou= nd 127 candela. =A0At 110 degrees (and 250) measured from the nose, the int= ensity is reduced=A0to 127 x cosine (70 degrees) = =3D 43 candela.

This is mo= re than twice the 20 candela requirement so yes, the LED/light pipe is brig= ht enough.

If I recall the o= ld Whelen aft-facing white light uses 2 amps, so it is impressive that a li= ttle LED drawing 700ma=A0can match it.





--
Jeff Peterson

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