X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 29 Jan 2010 10:31:50 -0500 Message-ID: X-Original-Return-Path: Received: from web36906.mail.mud.yahoo.com ([209.191.85.74] verified) by logan.com (CommuniGate Pro SMTP 5.3.2) with SMTP id 4102839 for lml@lancaironline.net; Thu, 28 Jan 2010 19:59:15 -0500 Received-SPF: none receiver=logan.com; client-ip=209.191.85.74; envelope-from=chris_zavatson@yahoo.com Received: (qmail 6030 invoked by uid 60001); 29 Jan 2010 00:58:40 -0000 DomainKey-Signature:a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com; h=Message-ID:X-YMail-OSG:Received:X-Mailer:Date:From:Subject:To:MIME-Version:Content-Type; b=v9iasdrbw3n0yoK3ujeM8eaHQIMcp0YEh/jOC5BaUGwITO6lTLyyctTwaAinAqSmGtGMOqqh5hT1sKKti7bBw7vPVH2wxieL8Oomo5XBFbEw3ZMnQFNfcq6OaJVpWiFfPdt0zAnwI4nFTrsxRxv7u/+Pw5zP1v8DEU7loVUfaFQ=; X-Original-Message-ID: <321291.5143.qm@web36906.mail.mud.yahoo.com> X-YMail-OSG: 50lLU7AVM1k_9bqa3uGes5KPJlbLXmrD4tw1nfa3KlWx973one6w6h0o4VzmnwdEUoDDKMyfbvBecbvxdaQmiRaQGohcrkGQxj7yikaolu4rVIBPLXoTSTHiGH0ZpkMOi0VP1COBufLo5hxvw.L1plsTqlOdeFh3ONUJ9Ui1v3ORENkhQDCK._8K3Poy191c2Q6RusuYZL..3k8OvhcPPZ.P5lsuLjDFCVJk.RwgRbqxFXTB1WVW34YVoMe2f2bJEawWo4VS.OO9Z904CzT62Sz5apE74vwr8Fb7jO07AoSYbuu.PFyAbA6vHvZ6IvLQ3HfQeE.d62piLl_FSU30N4VqTo_pgYlu_AfPQbjT7Gp7OnCtp73YCmJ9iNn9rFRk0wQ- Received: from [149.32.224.33] by web36906.mail.mud.yahoo.com via HTTP; Thu, 28 Jan 2010 16:58:40 PST X-Mailer: YahooMailRC/272.7 YahooMailWebService/0.8.100.260964 X-Original-Date: Thu, 28 Jan 2010 16:58:40 -0800 (PST) From: Chris Zavatson Subject: Re: [LML] Re: Airspeed sensing switch /Auto gear extension / Engine out gear down Issue! X-Original-To: Lancair Mailing List MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="0-1717823062-1264726720=:5143" --0-1717823062-1264726720=:5143 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: quoted-printable To find equivalent airspeed change for the same energy, look at the differe= nce of the speeds squared 1/2 x m x((v=A0+ dv)^2-v^2).=A0 It doesn't take m= uch change in forward velocity to generate the equivalent energy.=A0 This h= owever ignores all the drag/time issues, so this calculation underestimates= the speed increase required.=0AChris=0A=0A=0A=0A=0A_______________________= _________=0AFrom: Colyn Case at earthlink =0ATo: l= ml@lancaironline.net=0ASent: Thu, January 28, 2010 9:43:45 AM=0ASubject: [L= ML] Re: Airspeed sensing switch /Auto gear extension / Engine out gear down= Issue!=0A=0A=0AChris said,=0AAOA will compensate for weight very nicely.= =A0 It doesn't know, however, what descent rate is being flown and how much= energy is needed to arrest that sink.=A0 The energy needed goes up as a sq= uared function of the vertical speed.=A0 In the 360, I span descent rates f= rom 500 to 2,000 fpm on final (ILS to short approaches).=A0 The energy=A0th= us varies by a factor=A0~16.=A0 It is the higher end of the scale where one= can get=A0into trouble.=A0=A0=0A=0AIs "energy" equivalent to mv^2 in this = case?=A0=A0 =0Aso if you double your sink rate you would need to double you= r speed above stall to compensate?=0A=0A=0A --0-1717823062-1264726720=:5143 Content-Type: text/html; charset=iso-8859-1 Content-Transfer-Encoding: quoted-printable

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To find equivalent airspeed change for the same energy, look at= the difference of the speeds squared 1/2 x m x((v + dv)^2-v^2). = It doesn't take much change in forward velocity to generate the equivalent= energy. This however ignores all the drag/time issues, so this calcu= lation underestimates the speed increase required.

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Chris
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=0A<= SPAN style=3D"FONT-WEIGHT: bold">From: Colyn Case at earthlink &= lt;colyncase@earthlink.net>
To:<= /SPAN> lml@lancaironline.net
Se= nt: Thu, January 28, 2010 9:43:45 AM
Subject: [LML] Re: Airspeed sensing switch /Auto ge= ar extension / Engine out gear down Issue!

=0A=0A=0A

<= EM>Chris said,

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AOA will compensate for weight = very nicely. It doesn't know, however, what descent rate is being flo= wn and how much energy is needed to arrest that sink. The energy need= ed goes up as a squared function of the vertical speed. In the 360, I= span descent rates from 500 to 2,000 fpm on final (ILS to short approaches= ). The energy thus varies by a factor ~16. It is the = higher end of the scale where one can get into trouble. &nbs= p;

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Is "energy"= equivalent to mv^2 in this case?

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so if you double your sink rate you would need to doubl= e your speed above stall to compensate?

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