X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Mon, 20 Jun 2005 16:08:03 -0400 Message-ID: X-Original-Return-Path: <5zq@cox.net> Received: from lakermmtao07.cox.net ([68.230.240.32] verified) by logan.com (CommuniGate Pro SMTP 4.3.4) with ESMTP id 1007948 for lml@lancaironline.net; Mon, 20 Jun 2005 15:59:22 -0400 Received-SPF: none receiver=logan.com; client-ip=68.230.240.32; envelope-from=5zq@cox.net Received: from OFFICE ([68.110.249.147]) by lakermmtao07.cox.net (InterMail vM.6.01.04.00 201-2131-118-20041027) with SMTP id <20050620195831.QPPR28809.lakermmtao07.cox.net@OFFICE>; Mon, 20 Jun 2005 15:58:31 -0400 X-Original-Message-ID: <00de01c575d2$39dbb850$6401a8c0@OFFICE> From: "Bill&Sue" <5zq@cox.net> X-Original-To: "Lancair Mailing List" X-Original-Cc: "Scott Krueger" References: Subject: Re: [LML] Re: Induction air filter X-Original-Date: Mon, 20 Jun 2005 15:57:01 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_00DB_01C575B0.B27B8320" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2180 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_00DB_01C575B0.B27B8320 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable If a bird (or piece of one) can actually get into my intake it will = probably be sucked right through since it would be so small -=20 Scott,=20 Actually, a bird has pretty good odds on getting to your air intake = without encountering a prop blade. The odds would be somewhere around 3 = 1/2 to 1 of success (although I'm sure that the bird wouldn't see it as = successful) depending on your speed, rpm and the size of the bird. At 180 knots, you're traveling about 18,216 feet per minute. At 2500 = rpm a blade is passing by the intake at the rate of 5,000 blades per = minute (for a two blade prop). That means that the airplane travels over = 3 1/2 feet between blade passes. A 1 foot long bird would have better = than 3 to 1 chance of getting through.=20 So what's it all mean, Mr. Natural? Uhhh, not much. Just that you = shouldn't count on your prop to mince avian airspace sharers into bite = size pieces. =20 That sure is an elegant intake system, though. Bill Harrelson 5zq@cox.net N5ZQ 320 1,000 hrs N6ZQ IV 2.063% ------=_NextPart_000_00DB_01C575B0.B27B8320 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
 
 
 If a bird (or piece of one) can actually get into my intake = it will=20 probably be sucked right through since it would be so small - =
 
 
 
 
Scott,
 
Actually, a bird has pretty good odds on getting to your air = intake=20 without encountering a prop blade. The odds would be somewhere around = 3 1/2 to=20 1 of success (although I'm sure that the bird wouldn't see it as = successful)=20 depending on your speed, rpm and the size of the bird.
 
At 180 knots, you're traveling about 18,216 feet per minute. At = 2500 rpm=20 a blade is passing by the intake at the rate of 5,000 blades per = minute (for a=20 two blade prop). That means that the airplane travels over 3 1/2 feet = between=20 blade passes. A 1 foot long bird would have better than 3 to = 1=20 chance of getting through.
 
So what's it all mean, Mr. Natural?  Uhhh, not much. Just = that you=20 shouldn't count on your prop to mince avian airspace sharers into = bite=20 size pieces.  
 
That sure is an elegant intake system, though.
 
 
Bill Harrelson
N5ZQ  320  1,000 hrs
N6ZQ   IV   =20 2.063%
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