Return-Path: Sender: "Marvin Kaye" To: lml@lancaironline.net Date: Fri, 18 Feb 2005 13:01:21 -0500 Message-ID: X-Original-Return-Path: Received: from mta13.adelphia.net ([68.168.78.44] verified) by logan.com (CommuniGate Pro SMTP 4.3c1) with ESMTP id 744170 for lml@lancaironline.net; Fri, 18 Feb 2005 09:21:36 -0500 Received-SPF: pass receiver=logan.com; client-ip=68.168.78.44; envelope-from=glcasey@adelphia.net Received: from worldwinds ([70.32.213.236]) by mta13.adelphia.net (InterMail vM.6.01.03.04 201-2131-111-106-20040729) with SMTP id <20050218142050.GZSV14286.mta13.adelphia.net@worldwinds> for ; Fri, 18 Feb 2005 09:20:50 -0500 From: "Gary Casey" X-Original-To: "lancair list" Subject: RE: Air intake formula X-Original-Date: Fri, 18 Feb 2005 06:17:24 -0800 X-Original-Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset="Windows-1252" Content-Transfer-Encoding: 7bit X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook IMO, Build 9.0.2416 (9.0.2910.0) Importance: Normal X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 <> Lorn, The calculations you presented appear to recommend the inlet to be sized for a 1:1 velocity ratio - in other words the velocity in the inlet is equal to the free airstream velocity. I see other recommendations that are for velocity ratios between 0.4 and 0.7, producing much of the pressure recovery ahead of the inlet. The advantage of that, as I see it, is that pressure recovery ahead of the inlet is quite efficient and requires less recovery inside the duct, reducing the required length. Also, at lower airspeeds the inlet is more efficient as there is less chance for flow separation inside the duct. What do you think? Gary Casey