Return-Path: Sender: (Marvin Kaye) To: lml@lancaironline.net Date: Thu, 03 Jun 2004 22:01:32 -0400 Message-ID: X-Original-Return-Path: Received: from c60.cesmail.net ([216.154.195.49] verified) by logan.com (CommuniGate Pro SMTP 4.2b4) with ESMTP-TLS id 122930 for lml@lancaironline.net; Thu, 03 Jun 2004 19:18:51 -0400 Received: from unknown (192.168.1.30) by c60.cesmail.net with QMQP; 03 Jun 2004 19:18:20 -0400 Received: from 12.146.136.195 ([12.146.136.195]) by webmail.spamcop.net (Horde) with HTTP for ; Thu, 3 Jun 2004 16:18:20 -0700 X-Original-Message-ID: <20040603161820.fjgymocc04kcgogc@webmail.spamcop.net> X-Original-Date: Thu, 3 Jun 2004 16:18:20 -0700 From: bob mackey X-Original-To: lml@lancaironline.net Subject: Pitot pressure in lb/sq in or inches WG MIME-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Disposition: inline Content-Transfer-Encoding: 7bit User-Agent: Internet Messaging Program (IMP) 4.0-cvs > Somebody on the list once gave a formula or a conversion method to take > airspeed and convert it into units of pressure. > > Due to my gear up landing I want to fit a pressure switch in the pitot line. > I need to know how to convert airspeed into pressure units in order to buy > the correct switch. Electronics catalogs have adjustable pressure switches > at under $20. The "dynamic pressure" measured by a pitot tube, relative to the static port, is: Q = 0.5 * rho * V^2 Where rho is the density of air, and V is the forward speed. In reasonable units (approximating 200 kts at sea level), Q = 0.5 * 1.225 kg/m^3 * 100 m/sec = 6125 Pa in screwy american units, that's 0.888 psi. If you want the gear warning to come on below say 80 kias (~40 m/sec), then Q = 980 Pa = 0.142 psi. - bob mackey flying a 235 building a 320 103MD -at- pure-flight.com [use this email address - the one at the top is spam bait]