In a message dated 6/1/2004 5:43:33 PM Central Standard Time,
Charles.Nelson@therasense.com writes:
Does anyone know the CFM required
for the IO360B1F?
Charles,
Try this, Each cylinder sucks a load of air every second revolution.
So two cylinders suck in air every revolution. So, at WOT, 360/2 =
180 CI per revolution. At 2700 RPM, that is 2700 x 180 = 486000 CI/M or
486000/ (12x12x12) = 486000/1728 = 281.25 CFM In other words, a room, 5' x
7' (with an 8 foot ceiling) would contain the air your engine would need for one
minute at sea-level take-off power. Also, at sea level, air weighs
.0807/CF so we would need 22.7 pounds of air per minute and 1.5 pounds of
fuel (approx 15:1 ratio). This works out to about 1/4 gallon per min or 15
gal/hr.
What was that question again?
Scott Krueger
AKA Grayhawk
Sky2high@aol.com
II-P N92EX IO320 Aurora, IL
(KARR)
LML, where ideas collide and you
decide!