Mailing List lml@lancaironline.net Message #23995
From: <Sky2high@aol.com>
Sender: Marvin Kaye <marv@lancaironline.net>
Subject: Re: [LML] Air Intake volume for IO360 B1F
Date: Tue, 01 Jun 2004 20:20:06 -0400
To: <lml@lancaironline.net>
In a message dated 6/1/2004 5:43:33 PM Central Standard Time, Charles.Nelson@therasense.com writes:

Does anyone know the CFM required for the IO360B1F?

Charles,
 
Try this, Each cylinder sucks a load of air every second revolution.  So two cylinders suck in air every revolution.  So, at WOT,  360/2 = 180 CI per revolution.  At 2700 RPM, that is 2700 x 180 = 486000 CI/M or 486000/ (12x12x12) = 486000/1728 = 281.25 CFM  In other words, a room, 5' x 7' (with an 8 foot ceiling) would contain the air your engine would need for one minute at sea-level take-off power.  Also, at sea level, air weighs .0807/CF so we would need 22.7 pounds of air per minute and 1.5 pounds of fuel (approx 15:1 ratio).  This works out to about 1/4 gallon per min or 15 gal/hr.
 
What was that question again?
 
Scott Krueger AKA Grayhawk
Sky2high@aol.com
II-P N92EX IO320 Aurora, IL (KARR)

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