Return-Path: Sender: (Marvin Kaye) To: lml@lancaironline.net Date: Sun, 30 May 2004 11:33:09 -0400 Message-ID: X-Original-Return-Path: Received: from tomts22-srv.bellnexxia.net ([209.226.175.184] verified) by logan.com (CommuniGate Pro SMTP 4.2b3) with ESMTP id 96879 for lml@lancaironline.net; Sun, 30 May 2004 10:34:07 -0400 Received: from crowe ([67.69.55.194]) by tomts22-srv.bellnexxia.net (InterMail vM.5.01.06.10 201-253-122-130-110-20040306) with SMTP id <20040530143336.CYCJ14757.tomts22-srv.bellnexxia.net@crowe> for ; Sun, 30 May 2004 10:33:36 -0400 X-Original-Message-ID: <002401c44653$2f3c5710$6721fea9@crowe> From: "Ian Crowe" X-Original-To: "Lancair Mailing List" Subject: LNC2 rod end X-Original-Date: Sun, 30 May 2004 10:34:15 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0021_01C44631.A7CBF540" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1409 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1409 This is a multi-part message in MIME format. ------=_NextPart_000_0021_01C44631.A7CBF540 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Yes I had the rod end shear off. I am convinced that the geometry of = the system is all wrong. By this I mean that when you need the cylinder = to completely close the door it is at a point where most of the pull = from the cylinder is parallel to the door. Also I feel that the = cylinder should be to free to pivot about its mounting point. This is = due o the fact that the operating end moves in arc to close the door. = If the cylinder cannot pivot the force will impose a bending moment on = the rod end and of course the rest of the system. Hope that helps. Ian Crowe ------=_NextPart_000_0021_01C44631.A7CBF540 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Yes I had the rod end shear off.  = I am=20 convinced that the geometry of the system is all wrong.  By this I = mean=20 that when you need the cylinder to completely close the door it is at a = point=20 where most of the pull from the cylinder is parallel to the door.  = Also I=20 feel that the cylinder should be to free to pivot about its = mounting=20 point.  This is due o the fact that the operating end moves in arc = to close=20 the door.  If the cylinder cannot pivot the force will impose a = bending=20 moment on the rod end and of course the rest of the system.
 
Hope that helps.
 
Ian Crowe
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