Return-Path: Received: from enaila.nidlink.com ([216.18.128.8]) by truman.olsusa.com (Post.Office MTA v3.5.1 release 219 ID# 0-52269U2500L250S0V35) with ESMTP id com for ; Sat, 24 Apr 1999 10:59:29 -0400 Received: from regandesigns.com (tnt132-95.nidlink.com [216.18.132.95]) by enaila.nidlink.com (8.9.0/8.9.0) with ESMTP id IAA16775 for ; Sat, 24 Apr 1999 08:01:51 -0700 (PDT) Message-ID: <3721DC5B.175C1B32@regandesigns.com> Date: Sat, 24 Apr 1999 07:59:39 -0700 From: Brent Regan To: lancair.list@olsusa.com Subject: Hydraulic Manifolds References: <19990424041454.AAA22625@truman.olsusa.com> X-Mailing-List: lancair.list@olsusa.com Mime-Version: 1.0 <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> << Lancair Builders' Mail List >> <<<<<<<<<<<<<<<<--->>>>>>>>>>>>>>>> >> The design of hydraulic fittings is relatively straight forward. The first thing you have to understand are the terms used. In particular are "Rated pressure", "Yield Pressure" and "Burst pressure". Burst pressure is the point where something ruptures, yield pressure produces a stress in the component greater than the yield strength but less than the tensile strength. Rated pressure is generally 1/3 of the burst pressure for hoses and 1/3 the yield pressure for metal components (safety factor of 3 and a margin of safety of 2). Calculating the stress in a round pipe is easy. The formula is Pressure X Inside Radius/ Wall Thickness. So a piece of 1/4" x 0.035 tubing at 1500psi would have a stress of (1500 X 0.090/.035)= 3857psi. Dead soft aluminum tubing has a a yield strength of around 12ksi (1ksi = 1000psi) and a third of 12000 is 4000psi, the rated pressure of this tube in aluminum. As you can see by the formula, small diameter tubes with thick walls can resist high pressures with low stress levels. This is why the "fish tank tubing" works in the brake systems. Of course it does not take into account aging, abuse or heat, three things brakes are good at. For rectangular section manifolds the variation in wall thickness tends to concentrate the stresses in the thin areas therefore, as a rule, I multiply safety factor by 1.5, from 3 to 4.5, and use the thinnest portion of the wall for T. So lets say you drive down to Ace and buy a chunk 1 X 1 square stock of what looks like aluminum to build your manifold. You decide to use 3/8 pipe fittings so you drill some 37/64 (0.578) holes for the tap. One of the holes is 0.050 off center, oops. How much pressure will your manifold endure? S = P X R / T therefore P = S X T / R S = 4000 / 1.5 = 2666 R = (0.578 / 2) = 0.289 T = ((1.00 - 0.578) / 2) - 0.050 = 0.161 P= 2666 X 0.161 / 0.289 = 1485 psi I like monolithic manifolds because I hate leaks and the "fitting farm" manifolds leak, and they are expensive. I would also use a piece of "known alloy and temper" material. Hey Billy Bob, git me a chunk of that silvery stuf with the white spots on it from under the tahr of yur Trans Am. Brent Regan [Since I want to use 1/8NPT in my piece of 1^2 stock, and to do the entire assembly out of 6061T6, based on the formulae you've provided it looks like I'll be more than ok. Thanks for the info. (I hate leaks too!) ] >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> LML homepage: http://www.olsusa.com/Users/Mkaye/maillist.html