Return-Path: Received: from imf25aec.mail.bellsouth.net ([205.152.59.73] verified) by logan.com (CommuniGate Pro SMTP 4.2b2) with ESMTP id 3209895 for flyrotary@lancaironline.net; Thu, 06 May 2004 23:31:17 -0400 Received: from TOSHIBAjhr ([209.214.14.183]) by imf25aec.mail.bellsouth.net (InterMail vM.5.01.06.08 201-253-122-130-108-20031117) with SMTP id <20040507033116.TIVR15189.imf25aec.mail.bellsouth.net@TOSHIBAjhr> for ; Thu, 6 May 2004 23:31:16 -0400 From: "John Slade" To: "Rotary motors in aircraft" Subject: RE: [FlyRotary] Re: fuel injector prices Date: Thu, 6 May 2004 23:31:15 -0400 Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook IMO, Build 9.0.2416 (9.0.2910.0) Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 > 550 cc/min = 0.1453 Gallons. So 0.1453 Gallons * 60 (minutes) = 8.718 > Gallons/ hour x 6 (lbs/gallon) = 52 lbs/ hr. Or a 550 cc/min > injector would > flow approx 52 lbs of fuel if it flowed wide open for one hour or > 52 lbs/hr. > > for the NA engines the stock injector is the 460 cc/min (sometimes they > varied a bit around that figure) > 460 cc/min = 0.1215191gallons so performing the same > calculations = 7.29114 > gallons/hr x 6 = 43.75 lbs/hour Ed. Thanks. I follow that. So with 4 of these 550cc suckers going full belt I'd be capable of expelling 52/6 * 4 = 34.67 gals/hr. Seems a bit excessive! Also - does fuel pressure factor into the equasion? John