X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from [24.25.9.102] (HELO ms-smtp-03-eri0.southeast.rr.com) by logan.com (CommuniGate Pro SMTP 5.0.7) with ESMTP id 963754 for flyrotary@lancaironline.net; Wed, 01 Feb 2006 13:38:47 -0500 Received-SPF: pass receiver=logan.com; client-ip=24.25.9.102; envelope-from=eanderson@carolina.rr.com Received: from edward2 (cpe-024-074-025-165.carolina.res.rr.com [24.74.25.165]) by ms-smtp-03-eri0.southeast.rr.com (8.13.4/8.13.4) with SMTP id k11IbxUB002498 for ; Wed, 1 Feb 2006 13:38:01 -0500 (EST) Message-ID: <000f01c6275e$a44fcc60$2402a8c0@edward2> From: "Ed Anderson" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: Suitability of NPG for Rotary Engine use Date: Wed, 1 Feb 2006 13:38:05 -0500 MIME-Version: 1.0 Content-Type: text/plain; format=flowed; charset="iso-8859-1"; reply-type=response Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2180 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 X-Virus-Scanned: Symantec AntiVirus Scan Engine ----- Original Message ----- From: "Ernest Christley" To: "Rotary motors in aircraft" Sent: Wednesday, February 01, 2006 12:11 PM Subject: [FlyRotary] Re: Suitability of NPG for Rotary Engine use > Ed Anderson wrote: > >> Ernest, my admittedly limited understanding of thermo properties leaves >> me to believe that specific heat already takes into consideration the >> different in density. In otherwords, the specific heat factor specifies >> how much heat it takes to raise a fixed amount of a material (cubic CC?) >> 1 degree. Therefore, the role density plays is already taken into account >> by determining the specific heat of the material. At least that is my >> understanding. > > The units in the chart are given as Btu/lb/*F, so that is the amount of > heat necessary to raise the temperature of certain mass. A higher density > will allow more mass to pass by at the same flow rate. I don't think the > 10% difference in density would change your conclusions (which I think are > valid), but it would help explain the discrepancy in their performance > numbers. > > -- Ok, I see what you mean. I'm not certain to be honest. But your are right in that Q = cp*Mass*DeltaT, so if Mass goes up so does heat transfer. So that certainly helps in that direction. Ed