X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: <13brv3@bellsouth.net> Received: from imf17aec.mail.bellsouth.net ([205.152.59.65] verified) by logan.com (CommuniGate Pro SMTP 4.3c5) with ESMTP id 936918 for flyrotary@lancaironline.net; Sun, 08 May 2005 22:21:04 -0400 Received-SPF: pass receiver=logan.com; client-ip=205.152.59.65; envelope-from=13brv3@bellsouth.net Received: from rd ([65.6.194.9]) by imf17aec.mail.bellsouth.net (InterMail vM.5.01.06.11 201-253-122-130-111-20040605) with ESMTP id <20050509022017.MHIY2428.imf17aec.mail.bellsouth.net@rd> for ; Sun, 8 May 2005 22:20:17 -0400 From: "Russell Duffy" <13brv3@bellsouth.net> To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: 4-port intake measurements Date: Sun, 8 May 2005 21:20:20 -0500 Message-ID: <000001c5543d$a7bdcfe0$6101a8c0@rd> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0001_01C55413.BEE7C7E0" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2527 This is a multi-part message in MIME format. ------=_NextPart_000_0001_01C55413.BEE7C7E0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable For 7000 rpm 60/3500 =3D .017 sec. .017/6 =3D .00286 sec or 2.86 = millsec. .00286 *1100 =3D 3.14 ft or 1/2 of that would be 1.5 ft or 18" for a = runner length, at least if my math is correct. This is only an approximation = but should give you an idea of lengths. =20 =20 Hi Ed, =20 Was this a test to see if I was paying attention? Shouldn't this be = 7000 rpm 60/2333=3D .026 sec ? Either way, these lengths seem mightly long = for the cowl space I have. =20 =20 Thanks for taking a look at this. I'm not sure what I'll do, but I also need to get rid of this #%&@ oil leak first. I made some progress on = it, and hope I've got it beat now. Won't know how wrong I am until next = time I fly. =20 =20 Rusty (not kidding about the supercharger) =20 =20 ------=_NextPart_000_0001_01C55413.BEE7C7E0 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Message
For 7000 rpm 60/3500 =3D .017 sec.   .017/6 =3D = .00286 sec or 2.86=20 millsec.   .00286 *1100 =3D 3.14 ft or 1/2 of that would be = 1.5 ft or=20 18" for a runner length, at least if my math is correct.  This is = only an=20 approximation but should give you an idea of lengths.
 
 
Hi=20 Ed,
 
Was this a=20 test to see if I was paying attention?  Shouldn't this be 7000 rpm = 60/2333=3D=20 .026 sec ?  Either way, these lengths seem mightly long for the cowl = space I=20 have. 
 
Thanks for=20 taking a look at this.  I'm not sure what I'll do, but I also need = to get=20 rid of this #%&@ oil leak first.  I made some progress on it, = and hope=20 I've got it beat now.  Won't know how wrong I am until next time I=20 fly. 
 
Rusty (not=20 kidding about the supercharger)
 
 
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