X-Virus-Scanned: clean according to Sophos on Logan.com X-SpamCatcher-Score: 2 [X] Return-Path: Sender: To: lml Date: Thu, 07 Dec 2006 13:11:20 -0500 Message-ID: X-Original-Return-Path: Received: from smtp109.sbc.mail.mud.yahoo.com ([68.142.198.208] verified) by logan.com (CommuniGate Pro SMTP 5.1.3) with SMTP id 1650761 for lml@lancaironline.net; Thu, 07 Dec 2006 11:37:05 -0500 Received-SPF: none receiver=logan.com; client-ip=68.142.198.208; envelope-from=elippse@sbcglobal.net Received: (qmail 96900 invoked from network); 7 Dec 2006 16:36:21 -0000 DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=sbcglobal.net; h=Received:Message-ID:From:To:Subject:Date:MIME-Version:Content-Type:X-Priority:X-MSMail-Priority:X-Mailer:X-MimeOLE; b=hbqdQ19KjFUDLHZuS9GkrO7CQ7alhOsShg3hik/DelMWk5VUTiqwSvl1TcfrqyC2xpjG7+LEU95aNQ+eJAU8jH5RUFqbLy9L2YlrdpR2ounJbcaMpUy1gYo++m6fZbomacmPwL7sEdxQm8cujxx56UrcLKawUWdlmA7AbxPY8MM= ; Received: from unknown (HELO Computerroom) (elippse@sbcglobal.net@75.15.138.255 with login) by smtp109.sbc.mail.mud.yahoo.com with SMTP; 7 Dec 2006 16:36:20 -0000 X-Original-Message-ID: <000801c71a1d$d61e4430$ff8a0f4b@Computerroom> From: "Paul Lipps" X-Original-To: "Marv Kaye" Subject: Easily excited X-Original-Date: Thu, 7 Dec 2006 08:36:15 -0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0005_01C719DA.C1ED2E60" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2869 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2962 This is a multi-part message in MIME format. ------=_NextPart_000_0005_01C719DA.C1ED2E60 Content-Type: text/plain; charset="Windows-1252" Content-Transfer-Encoding: quoted-printable 'Guess I don't quite understand the scenario of why the regulator, which = supplies the excitation to the alternator field, would get disconnected = if the battery post disconnected. There would have to be some = interruption in the circuit from the battery to the regulator. As long = as the alternator is still connected to the buss which supplies the = regulator, the alternator should maintain regulation, even without the = battery connected to the buss, as long as there is some load, which = could even be the alternator field through the regulator. This is why I = had recommended in an earlier post that the regulator's field supply = connection be made to the alternator side of an alternator circuit = breaker, if present, to prevent voltage runaway. Please expand on the = scenario! Thanks ------=_NextPart_000_0005_01C719DA.C1ED2E60 Content-Type: text/html; charset="Windows-1252" Content-Transfer-Encoding: quoted-printable
'Guess I don't quite understand the scenario of = why the=20 regulator, which supplies the excitation to the alternator field, would = get=20 disconnected if the battery post disconnected. There would have to be = some=20 interruption in the circuit from the battery to the regulator. As long = as the=20 alternator is still connected to the buss which supplies the regulator, = the=20 alternator should maintain regulation, even without the battery = connected to the=20 buss, as long as there is some load, which could even be the alternator = field=20 through the regulator. This is why I had recommended in an earlier post = that the=20 regulator's field supply connection be made to the alternator side of an = alternator circuit breaker, if present, to prevent voltage runaway. = Please=20 expand on the scenario!  Thanks
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