Mailing List lml@lancaironline.net Message #21425
From: Christopher Zavatson <Christopher.Zavatson@udlp.com>
Sender: Marvin Kaye <marv@lancaironline.net>
Subject: [LML] Fw: [LML] Re: Braking Energy
Date: Thu, 13 Nov 2003 20:55:50 -0500
To: <lml@lancaironline.net>
emjones@charter.ne writes:
<<E=0.44 X 10^3 X 10^2 X 10^2=0.44 X 10^7=4.4 X 10^6 lb-ft

If we look at the kinetic energy per wheel, then the braking energy per
wheel is

E=1/2 WV^2

W=pounds "mass"=10^3
V=100 knots=170 feet/second
E=1/2 X 10^3 X 170 X 170=14.5 X 10^6   (over 3 X more)

What gives?>>

The units for mass are slugs not pounds.  Divide the weight by 32.1
ft/s^2 to get slugs . Also, the original equation had 0.044, but you
used 0.44.  After those changes you'll get the same result.

Chris Zavatson
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