Sender: <marv@lancaironline.net> (Marvin Kaye)
To: lml
Date: Thu, 21 Nov 2002 21:47:29 -0500
Message-ID: <redirect-1884077@logan.com>
Mime-Version: 1.0
From: "Lorn H. Olsen" <lorn@dynacomm.ws>
Subject: Back Flying
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My gear hydraulics are fixed and I am back flying again.

Besides an internal leak in the pump and a reversed spool valve, the 
right hydraulic strut had an internal leak.

It doesn't make me happy to have just spent over $2,500 but this is 
to let the REAL builders know how happy you should be to be able to 
fix your own planes.

On my test flight, I went over to Livingston County(KOZW) in SE 
Michigan and saw Tom Byrnes and Charley Kohler flying Tom's new LIVP. 
It is a beautiful airplane.

I cruised over at 1,500 ft, 7.6 gal/hr, 55% power and 175 ktas.

My engine uses 10 gal/hr at 75% power. Every .6 gal/hr below that 
figure is a 5% reduction in power. This comes from the engine manual. 
Therefore, to calculate my power, I subtract the fuel burn from 10 
and divide by .6. I then multiply that number by 5% and subtract it 
from 75%. In the above example that would be:

    1)   ( 10 - 7.6 ) = 2.4
    2)   2.4 / .6 = 4
    3)   4 * 5% = 20%
    4)   75% - 20% = 55%

I am open to suggestions as to any other way to calculate the power used?
-- 
Lorn H. 'Feathers' Olsen, MAA, DynaComm, Corp.
248-478-4301, mailto:lorn@dynacomm.ws
LNC2, O-320-D1F, N31161, Y47, SE Michigan