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Scott,

The formula you are thinking of is good old Ohm's Law which states that
E=IxR (E=volts, I=current in amps, R=resistance in ohms).

Put in context of your discussion, you multiply the current draw (I) of the
starter by any resistance (R) between the battery and the starter (that's
out and back) to find the total voltage drop in the path i.e., from the
battery, thru the master contactor, the starter relay, various connections
plus the cable resistance to the starter and the resistance of the return
path to find the voltage drop (V).

If one assumes even as much as 0.1 ohm total resistance and the starter
draws 100 amps, you'll lose 10 volts in the wiring alone! Suffice it to say
that the starter circuit must be a very low resistance since only 0.02 ohms
at 100 amps will bring the voltage applied to the starter down to about 10
volts. Since the battery has an internal resistance, your nice hot 14 volt
RG will probably only be putting out 12 volts at that load and the path
resistance will shave off the other 2 volts.

When it comes to starter circuit resistance, low is definitely better!

Dan Schaefer

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