Return-Path: Received: from [24.93.47.44] (HELO ms-smtp-05-eri0.texas.rr.com) by logan.com (CommuniGate Pro SMTP 4.2b8) with ESMTP id 324276 for flyrotary@lancaironline.net; Fri, 16 Jul 2004 22:45:57 -0400 Received-SPF: error receiver=logan.com; client-ip=24.93.47.44; envelope-from=RDarrah@austin.rr.com Received: from dell (cs6669241-190.austin.rr.com [66.69.241.190]) by ms-smtp-05-eri0.texas.rr.com (8.12.10/8.12.7) with SMTP id i6H2jFBw018200 for ; Fri, 16 Jul 2004 21:45:27 -0500 (CDT) Message-ID: <00f301c46ba8$16efab60$6401a8c0@austin.rr.com> From: "Bob Darrah" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: 11th test flight Date: Fri, 16 Jul 2004 21:45:14 -0500 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_00F0_01C46B7E.2D9C8420" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1106 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 X-Virus-Scanned: Symantec AntiVirus Scan Engine This is a multi-part message in MIME format. ------=_NextPart_000_00F0_01C46B7E.2D9C8420 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Al, OK, so my gyro tumbled a little. Back to needle, ball and airspeed = until I get this thing right side up! Thanks. Bob Darrah=20 =20 ----- Original Message -----=20 From: Al Gietzen=20 To: Rotary motors in aircraft=20 Sent: Friday, July 16, 2004 7:49 PM Subject: [FlyRotary] Re: 11th test flight Subject: [FlyRotary] Re: 11th test flight Al wrote: (big snip) "Just as speed increases at as the cube root of hp, so does it = decrease as the cube root of drag." Al, shouldn't that be: so does it decrease as the drag CUBED? No = guarantee's, but from memory (poor), I thought this would be closer. Bob Darrah Bob; Only if you are looking at it upside downJ. The speed changes as the = cube root of the hp or the drag; one directly and the other inversely. = If you start with the speed, you cube the ratio of the speed to get the = change in drag. So if the speed drops for 135 to 125; 135/125 =3D 1.08. = 1.08 cubed is 1.26. Drag has gone up 26%. Unless I have it wrong . . . Al ------=_NextPart_000_00F0_01C46B7E.2D9C8420 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

Al, OK, so my gyro tumbled a little. = Back to=20 needle, ball and airspeed until I get this thing right side up! =20 Thanks.

Bob Darrah

----- Original Message -----
From:=20 Al = Gietzen=20
To: Rotary motors in = aircraft

Sent: Friday, July 16, 2004 = 7:49 PM

Subject: [FlyRotary] Re: 11th = test=20 flight

Subject:=20 [FlyRotary] Re: 11th test flight

Al=20 wrote: (big snip)

"Just=20 as speed increases at as the cube root of hp, so does it decrease as = the cube=20 root of drag."

Al,=20 shouldn't that be: so does it decrease as the drag CUBED? No=20 guarantee's, but from memory (poor), I thought this would be=20 closer.

Bob=20 Darrah

Bob;

Only if = you are=20 looking at it upside downJ. = The speed=20 changes as the cube root of the hp or the drag; one directly and the = other=20 inversely. If you start with the speed, you cube the ratio of the = speed to get=20 the change in drag. So if the speed drops for 135 to 125; 135/125 =3D=20 1.08. 1.08 cubed is 1.26. Drag has gone up = 26%.

Unless I = have it=20 wrong . . .

Al

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