Return-Path: Sender: (Marvin Kaye) To: flyrotary Date: Sat, 07 Dec 2002 16:56:24 -0500 Message-ID: X-Original-Return-Path: Received: from mordor.vnet-inc.com ([216.129.224.17] verified) by logan.com (CommuniGate Pro SMTP 4.0.2) with ESMTP-TLS id 1895980 for flyrotary@lancaironline.net; Fri, 06 Dec 2002 11:03:52 -0500 Received: (qmail 81204 invoked by uid 89); 6 Dec 2002 17:30:52 -0000 Received: from unknown (HELO howard) (216.220.26.103) by mordor.vnet-inc.com with SMTP; 6 Dec 2002 17:30:51 -0000 X-Original-Message-ID: <200212062058590790.004855AC@smtp.ttc-cmc.net> In-Reply-To: References: X-Mailer: Calypso Version 3.20.02.00 (3) X-Original-Date: Fri, 06 Dec 2002 20:58:59 -0700 From: "Stone Tool" X-Original-To: "Rotary motors in aircraft" Subject: Re: [FlyRotary] Torque?? Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: quoted-printable Tommy: Torque is a non-issue. A given horsepower at a given RPM requires a given= amount of torque be produced. Torque is a static measurement of force.= Horsepower is the ability to do work. An example would be carrying= water up the stairs by the bucket. Torque would be the amount of water= you could carry per trip, and horsepower would be the amount of water you= could carry carry per hour. If you can carry two five gallon buckets of= water per trip you have twice the torque as someone who can only carry= one five gallon bucket, but if the guy with one bucket can make twice as= many trips he does the same amount of work as you do. A million pounds of= torque at zero RPM does no work at all.... it just sits there. Horsepower can be defined as Torque * RPM / 5252 If a 13B produces 140 horsepower @ 6000 RPM 140 * 5252 / 6000 =3D= 122.54 lbs torque @ 6000 Put that through a 50% redrive and you end= up with 245 foot pounds at 3000. You must think in terms of generating horsepower...... Horsepower is the= ability to do work..... Oops I'm repeating myself. GENERATING TORQUE: There is only one way to increase torque....(aside from gearing down)= that is to increase air / fuel flow PER REVOLUTION. This can be= accomplished by improving induction design which generally assists only in= a limited range.... most such measures work primarily at high RPM. The= reason for this is that the resistance to airflow increases as the airflow= increases. You will note that peak torque is found at low RPM where= maximum airflow can be achieved. This can also be achieved by= supercharging an engine..... which has other undesirable effects including= increasing the compression to the extent that detonation is an issue, and= of course weight, and higher stresses. GENERATING HORSEPOWER To increase horsepower we need to increase airflow PER UNIT OF TIME. I= use cubic feet per minute as a standard measure of airflow. It takes= very close to 1.62 cubic feet per minute to produce one horsepower. We= can increase horsepower by increasing RPM. Simple...... open the= throttle. By using the appropriate gear reduction we can run our RPM= up to where we have the horsepower we need....... there's your increase in= torque. The extremists resort to such measures as peripheral ports and= turbocharging to achieve much higher than rated horsepower, and much less= than normal life expectancy and greatly reduced reliability. There are a lot of pie in the sky claims out there, and a lot of= mis-conceptions....... unfortunately we must operate in the real world= with real world limitations. You have about 140 horsepower to work= with..... all you need to do is determine what your optimum prop RPM is= based on diameter which you determine from gear clearance and your= intended operating speed...... do you want lots of low end thrust or a= high cruise speed? High cruise speed does not require nearly as large of= a prop as good climb out, static and low speed operation. You then spec= out your reduction to match the desired prop RPM. Don't bother your head= about "torque"..... Interestingly you can convert horsepower directly into thrust at a given= forward speed if you know prop efficiency. Assuming a prop efficiency of= 80% which is realistic from around 100 mph upward through most of our= cruise ranges, you can use the following formula to work out your= thrust. (note that it does not work much below 100 mph because= efficiency falls off increasingly) Thrust =3D horsepower * (300/speed in mph). Thus your 140 horsepower= should give you 280 pounds of thrust at 150 mph Actually Thrust =3D horsepower* { (375*prop efficiency) / speed in mph }= Horsepower has to be real honest American Society of Automotive= Engineers Brake Horsepower for this to work. Note that at very low= speeds prop efficiency drops to near zero values, and in fact at zero= forward speed efficiency is at zero for all intents and purposes. Hope this helps clarify the issue...... there are way too many people out= there trying to cloud it. H.W. *********** REPLY SEPARATOR *********** On 12/5/02 at 6:06 PM Tommy James wrote: >Hi Guys and Kathy, Happy Christmas! > >Does anyone have ideas about how much torque@rpm the typical aviation >installation makes with a NA 13B? Also some elementary principles on the >variables of generating torque would be helpful. > >TIA >Tommy James<>< > > >>> Homepage: http://www.flyrotary.com/