X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from nm3-vm0.access.bullet.mail.mud.yahoo.com ([66.94.237.136] verified) by logan.com (CommuniGate Pro SMTP 5.4.1) with SMTP id 5123191 for flyrotary@lancaironline.net; Tue, 13 Sep 2011 15:23:52 -0400 Received-SPF: none receiver=logan.com; client-ip=66.94.237.136; envelope-from=ceengland@bellsouth.net Received: from [66.94.237.199] by nm3.access.bullet.mail.mud.yahoo.com with NNFMP; 13 Sep 2011 19:23:16 -0000 Received: from [66.94.237.122] by tm10.access.bullet.mail.mud.yahoo.com with NNFMP; 13 Sep 2011 19:23:16 -0000 Received: from [127.0.0.1] by omp1027.access.mail.mud.yahoo.com with NNFMP; 13 Sep 2011 19:23:16 -0000 X-Yahoo-Newman-Id: 649450.21950.bm@omp1027.access.mail.mud.yahoo.com Received: (qmail 24331 invoked from network); 13 Sep 2011 19:23:16 -0000 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=bellsouth.net; s=s1024; t=1315941796; bh=szP1toBjHPJxz6ZxYfBZVBCrVXzR831jQ7BDEhG0ZUE=; h=X-Yahoo-Newman-Property:X-YMail-OSG:X-Yahoo-SMTP:Received:Message-ID:Date:From:User-Agent:MIME-Version:To:Subject:References:In-Reply-To:Content-Type:Content-Transfer-Encoding; b=4wO4x7iboyCjlIrQ0tQaIcdhyt7HycjgbL28FZmP2cL0afai1LWrpGSZUNcyVejD0AkbyzGrM9krY4sG+DGDWNqzZIlEYDICOkopVYS/pycai7FCLWMJrTSnjEQL+Zhxt13mXH0z02xDlzFREgAHNrcQqVbqN8WrdmS94q5DSjY= X-Yahoo-Newman-Property: ymail-3 X-YMail-OSG: xsh_31QVM1nu.zIOulcL7FLgNnzsWlaOKEhNWsJRZhlUSFo gTb56pfegQqPWvWBqLDIWYEEoYM1Q4qqUhHqCErkwW.4lFd2H5bCkppBkWaE nN4Mbel2Qsg_fRWR9cHnpsoUU67U6ijzSKWfKMnobXKML7wWIi_YHRRKPgxD 2FCYyxOExUtNbITQz8TR1oQPgJ_EL0Rnc2e_61or_.6.j_wKeZyz2FIHpXFA SkoHkxzZaoJEGdj.pZw26FwceKTxbkr426PzNePfyqRo4wBsnpRksOHorXk7 IAGIkpmvY106ybFmFizanzVLTxYOWZuliFCu0OoOcJX2.T2YZiJD7uWnpkTy m8ogbE1pzk9DPzKin131_VSnpPj5F_yV0y_GCp4_S8D74vPajaQYEMlElQsL LUIoRm7i4sL.PqwFJND0HdpA138YmookaXFqEiFuLIhsSCQdbTCj1rFWtGhy T8HKMhggJyjtVDdhDNHtoLbczeHgLgLW4EPhT2.PTfoDj.Y1aA4zhIkV5Mxr GW5Fvo6fPJsgHcpQZyBX.rr3otQhDk90xw98ZVqalsTjJlxE7eXOlk5yExio vTTc- X-Yahoo-SMTP: uXJ_6LOswBCr8InijhYErvjWlJuRkoKPGNeiuu7PA.5wcGoy Received: from [192.168.10.6] (ceengland@98.95.176.26 with plain) by smtp101.sbc.mail.mud.yahoo.com with SMTP; 13 Sep 2011 12:23:16 -0700 PDT Message-ID: <4E6FADA4.4010603@bellsouth.net> Date: Tue, 13 Sep 2011 14:23:16 -0500 From: Charlie England User-Agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.2.21) Gecko/20110831 Thunderbird/3.1.13 MIME-Version: 1.0 To: Rotary motors in aircraft Subject: Re: [FlyRotary] Re: K & W Konfusion References: In-Reply-To: Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit Hi Ed, 1st, I'm afraid you have unwarranted excess confidence in my knowledge. :-) Thanks for the expansion (pardon the pun...) on what K&W is trying to say. I'm beginning to get a little bit of a handle on what's actually happening, & I'm hoping to be able to get a reasonable estimate of the performance differences between a straight duct & small face, thick rad & a wedge with larger face, thin rad (like Tracy's -8 & some others now flying). I'm also really interested in the potential drag reductions from exit ducts for higher speed planes like most of us are flying or building. Charlie On 09/11/2011 05:59 PM, Ed Anderson wrote: > > One, additional thing might be worth porting out is that with the > vector quantity Vb = Vi +Vt with Vt the component tangential to the > face of the core - as you might imagine, you don't get a lot of > cooling contribution due to Vt, as theoretically it doesn't contribute > (much) to the flow through the core (at least that is how I read it). > Therefore the condition where vb = vi with vt = 0 probably means > maximum cooling effect from the air flow which (one reason) is why > straight in flowing ducts (where Vb = Vi) cool better than one with > twists and turns. > > Ed > -------------------------------------------------- > From: "Ed Anderson" > Sent: Sunday, September 11, 2011 6:08 PM > To: "Rotary motors in aircraft" > Subject: [FlyRotary] Re: K & W Konfusion > >> Hi Charlie, >> >> Having pulled my hair out over some things in Chapter 12 of K& W, I >> can empathize. Let me see if I can help you with this particular >> question. >> >> As you know, Vb is a vector quantify having both magnitude and >> direction and here is composed of two vector quantities: Vi - >> (vector in line or incident with the core) and Vt (vector >> tangential to the face of the core). In this case ( a special case of >> the straight duct) Vt = 0. No, the first chapter does NOT spell this >> out, so you did not miss it, but when you examine figure 12.6 you >> will see it. >> >> In your first reference the Vt value = 0 (they do not point this out) >> and Vb is therefore equal solely to Vi (or the vector parallel to >> the duct, straight into the core). So here Vb = Vi because Vt = 0, >> straight duct condition only. >> >> Now in figure 12.6 the incoming oblique air flow does have two >> components (Vi and Vt) relative to the orientation of the block - Vt >> is not zero here and of course neither is Vi. So Vb = Vi + Vt. If >> you have a good copy and look carefully you can see that at the >> bottom of the vector triangle it shows Vb as the vector sum of Vi and >> Vt- and Vb is pointed in the direction of the airflow through the >> core (or parallel to the holes through the core or perpendicular to >> the core face). >> >> If you look at figure 12-7, the same vector combination is there and >> a bit easier to see. So in effec,t your first reference to Vb in >> chapter 12 is a special case of the overall vector components of the >> airflow (Vi and Vt) except in that case Vt = 0 and Vb = Vi. >> >> So it is probably more correct to say that Vb is the vector sum of >> the incident and tangential vectors of airflow or Vb is the vector >> expression of the airflow through the core. >> >> What is missing in figure 12.6 is the showing the vector sum of Vb >> AFTER it exits the core. If they did, what you would probably see >> is Vt much smaller or zero and Vb = Vi (since the duct is straight >> after the core). So if the vector sum on the one side of the core is >> Vb then it will also be Vb on the opposite side of the core - however >> the values of the vector components vi and vt will be different (if >> not a straight duct) - but their sum will remain the same - vb. >> >> At least that is the way I read it - and no, I've never found and K&W >> for dummies - if you do please let me know. >> >> >> Dummy Ed >> >> Edward L. Anderson >> Anderson Electronic Enterprises LLC >> 305 Reefton Road >> Weddington, NC 28104 >> http://www.andersonee.com >> http://www.eicommander.com >> >> >> -------------------------------------------------- >> From: "Charlie England" >> Sent: Sunday, September 11, 2011 3:13 PM >> To: "Rotary motors in aircraft" >> Subject: [FlyRotary] K & W Konfusion >> >>> Anyone else having problems interpreting K & W's chapter 12 on cooling? >>> >>> I confess to only having available (downloaded) chapters on inlets >>> & cooling, but their use of terms is a bit hair-pulling for me. For >>> instance, VsubB is defined on the 1st page of the chapter as >>> 'velocity of the air ahead of the block' & diagrammed that way in >>> fig 12-1, then it's apparently diagrammed as the velocity *leaving* >>> the cooling block in fig 12-6. And quite a few of the terms don't >>> seem to be defined at all (this may be due to my failure to take a >>> physics course in college, & the 30+ year interval since my one >>> semester of Calculus...). >>> >>> If there's a 'K&W for Dummies' book, please recommend a source... >>> >>> Charlie >>> >>> -- >>> Homepage: http://www.flyrotary.com/ >>> Archive and UnSub: >>> http://mail.lancaironline.net:81/lists/flyrotary/List.html >>> >> >> -- >> Homepage: http://www.flyrotary.com/ >> Archive and UnSub: >> http://mail.lancaironline.net:81/lists/flyrotary/List.html >> > > -- > Homepage: http://www.flyrotary.com/ > Archive and UnSub: > http://mail.lancaironline.net:81/lists/flyrotary/List.html >