X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from cdptpa-omtalb.mail.rr.com ([75.180.132.121] verified) by logan.com (CommuniGate Pro SMTP 5.4.1) with ESMTP id 5121018 for flyrotary@lancaironline.net; Sun, 11 Sep 2011 18:59:46 -0400 Received-SPF: pass receiver=logan.com; client-ip=75.180.132.121; envelope-from=eanderson@carolina.rr.com Return-Path: X-Authority-Analysis: v=1.1 cv=clOQl2Kon9ihL0vqe5S6shCOWnQ8eDPHG/StQ1omz74= c=1 sm=0 a=a1jMGePA_MAA:10 a=8nJEP1OIZ-IA:10 a=SC71y0a/4S6V9vjVxUojGA==:17 a=ayC55rCoAAAA:8 a=Ia-xEzejAAAA:8 a=arxwEM4EAAAA:8 a=r1ClD_H3AAAA:8 a=pedpZTtsAAAA:8 a=7g1VtSJxAAAA:8 a=M_SIapqnEP7IgEIAWyEA:9 a=989EbFVZNC1-gLpRh8YA:7 a=wPNLvfGTeEIA:10 a=Qa1je4BO31QA:10 a=EzXvWhQp4_cA:10 a=eJojReuL3h0A:10 a=Nl3AnvHYrxQXvTmT:21 a=Ble8YAG5hH8z1NMq:21 a=SC71y0a/4S6V9vjVxUojGA==:117 X-Cloudmark-Score: 0 X-Originating-IP: 174.110.175.135 Received: from [174.110.175.135] ([174.110.175.135:55585] helo=EdPC) by cdptpa-oedge01.mail.rr.com (envelope-from ) (ecelerity 2.2.3.46 r()) with ESMTP id A8/00-15370-04D3D6E4; Sun, 11 Sep 2011 22:59:12 +0000 Message-ID: <2543E938BE9C43E4A59CF4DFABED8086@EdPC> From: "Ed Anderson" To: "Rotary motors in aircraft" References: In-Reply-To: Subject: Re: [FlyRotary] Re: K & W Konfusion Date: Sun, 11 Sep 2011 18:59:11 -0400 MIME-Version: 1.0 Content-Type: text/plain; format=flowed; charset="iso-8859-1"; reply-type=response Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal Importance: Normal X-Mailer: Microsoft Windows Live Mail 14.0.8117.416 X-MimeOLE: Produced By Microsoft MimeOLE V14.0.8117.416 One, additional thing might be worth porting out is that with the vector quantity Vb = Vi +Vt with Vt the component tangential to the face of the core - as you might imagine, you don't get a lot of cooling contribution due to Vt, as theoretically it doesn't contribute (much) to the flow through the core (at least that is how I read it). Therefore the condition where vb = vi with vt = 0 probably means maximum cooling effect from the air flow which (one reason) is why straight in flowing ducts (where Vb = Vi) cool better than one with twists and turns. Ed -------------------------------------------------- From: "Ed Anderson" Sent: Sunday, September 11, 2011 6:08 PM To: "Rotary motors in aircraft" Subject: [FlyRotary] Re: K & W Konfusion > Hi Charlie, > > Having pulled my hair out over some things in Chapter 12 of K& W, I can > empathize. Let me see if I can help you with this particular question. > > As you know, Vb is a vector quantify having both magnitude and direction > and here is composed of two vector quantities: Vi - (vector in line or > incident with the core) and Vt (vector tangential to the face of the > core). In this case ( a special case of the straight duct) Vt = 0. No, > the first chapter does NOT spell this out, so you did not miss it, but > when you examine figure 12.6 you will see it. > > In your first reference the Vt value = 0 (they do not point this out) and > Vb is therefore equal solely to Vi (or the vector parallel to the duct, > straight into the core). So here Vb = Vi because Vt = 0, straight duct > condition only. > > Now in figure 12.6 the incoming oblique air flow does have two components > (Vi and Vt) relative to the orientation of the block - Vt is not zero here > and of course neither is Vi. So Vb = Vi + Vt. If you have a good copy > and look carefully you can see that at the bottom of the vector triangle > it shows Vb as the vector sum of Vi and Vt- and Vb is pointed in the > direction of the airflow through the core (or parallel to the holes > through the core or perpendicular to the core face). > > If you look at figure 12-7, the same vector combination is there and a > bit easier to see. So in effec,t your first reference to Vb in chapter > 12 is a special case of the overall vector components of the airflow (Vi > and Vt) except in that case Vt = 0 and Vb = Vi. > > So it is probably more correct to say that Vb is the vector sum of the > incident and tangential vectors of airflow or Vb is the vector expression > of the airflow through the core. > > What is missing in figure 12.6 is the showing the vector sum of Vb AFTER > it exits the core. If they did, what you would probably see is Vt much > smaller or zero and Vb = Vi (since the duct is straight after the core). > So if the vector sum on the one side of the core is Vb then it will also > be Vb on the opposite side of the core - however the values of the vector > components vi and vt will be different (if not a straight duct) - but > their sum will remain the same - vb. > > At least that is the way I read it - and no, I've never found and K&W for > dummies - if you do please let me know. > > > Dummy Ed > > Edward L. Anderson > Anderson Electronic Enterprises LLC > 305 Reefton Road > Weddington, NC 28104 > http://www.andersonee.com > http://www.eicommander.com > > > -------------------------------------------------- > From: "Charlie England" > Sent: Sunday, September 11, 2011 3:13 PM > To: "Rotary motors in aircraft" > Subject: [FlyRotary] K & W Konfusion > >> Anyone else having problems interpreting K & W's chapter 12 on cooling? >> >> I confess to only having available (downloaded) chapters on inlets & >> cooling, but their use of terms is a bit hair-pulling for me. For >> instance, VsubB is defined on the 1st page of the chapter as 'velocity of >> the air ahead of the block' & diagrammed that way in fig 12-1, then it's >> apparently diagrammed as the velocity *leaving* the cooling block in fig >> 12-6. And quite a few of the terms don't seem to be defined at all (this >> may be due to my failure to take a physics course in college, & the 30+ >> year interval since my one semester of Calculus...). >> >> If there's a 'K&W for Dummies' book, please recommend a source... >> >> Charlie >> >> -- >> Homepage: http://www.flyrotary.com/ >> Archive and UnSub: >> http://mail.lancaironline.net:81/lists/flyrotary/List.html >> > > -- > Homepage: http://www.flyrotary.com/ > Archive and UnSub: > http://mail.lancaironline.net:81/lists/flyrotary/List.html >