X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: <alventures@cox.net> Received: from fed1rmmtao104.cox.net ([68.230.241.42] verified) by logan.com (CommuniGate Pro SMTP 5.3c4) with ESMTP id 4036631 for flyrotary@lancaironline.net; Wed, 23 Dec 2009 11:20:33 -0500 Received-SPF: none receiver=logan.com; client-ip=68.230.241.42; envelope-from=alventures@cox.net Received: from fed1rmimpo03.cox.net ([70.169.32.75]) by fed1rmmtao104.cox.net (InterMail vM.8.00.01.00 201-2244-105-20090324) with ESMTP id <20091223161957.YHMR16123.fed1rmmtao104.cox.net@fed1rmimpo03.cox.net> for <flyrotary@lancaironline.net>; Wed, 23 Dec 2009 11:19:57 -0500 Received: from BigAl ([72.192.128.205]) by fed1rmimpo03.cox.net with bizsmtp id LgKw1d0074S1t5C04gKwrm; Wed, 23 Dec 2009 11:19:56 -0500 X-VR-Score: -100.00 X-Authority-Analysis: v=1.1 cv=hxRkenI+XOLoHPjz51PhBd6+pm8nOe1puOOeXS7yE/Y= c=1 sm=1 a=Vegc0WxVmH5BHtpNDyThtA==:17 a=NB-te26q-JLC-l5d9ZIA:9 a=JB2MfBS6ycegNrDKPYEA:7 a=p6_tBt7TYfltX4a331Lyw_fqjLkA:4 a=KVoZRe9gm5njMNXRwRoA:9 a=fDsu-mntF0Bna0lL7pcA:7 a=Va6SwSTfVgvxAv3D1VVnpwDkRa8A:4 a=Vegc0WxVmH5BHtpNDyThtA==:117 X-CM-Score: 0.00 From: "Al Gietzen" <ALVentures@cox.net> To: "'Rotary motors in aircraft'" <flyrotary@lancaironline.net> Subject: Air Flow Question Date: Wed, 23 Dec 2009 08:20:37 -0800 Message-ID: <90EA3D29E8584A35A91FAB668D262B71@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0016_01CA83A8.CE881690" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6856 In-Reply-To: <list-4036505@logan.com> Thread-Index: AcqD1MEh6Zvp/kMAThGQQWx8GolPOAAEM1Ug X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.5579 Importance: Normal This is a multi-part message in MIME format. ------=_NextPart_000_0016_01CA83A8.CE881690 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable Tracy wrote: My 5" round inlet for the radiator looks ridiculously small compared to yours but so far it is cooling the 20B OK. =20 =20 Now that sort of boggles my mind as it seems to violate the laws of = physics. Let's just take a modest climb power of, say; 225 hp. At that power, = the energy going into the coolant is about 6000 Btu/min. In order to remove that amount of heat, at a typical air temp increase of 75 degrees; takes about 4000 cfm air flow. A 5" dia inlet is 0.14 sq feet, meaning an = average inlet velocity about 29,000 ft/min, or 330 mph. Even at 100 air temp increase (unlikely on a 90F day) it's 250 mph. And I'm guessing your = climb speed is half that. Similar math suggests you'd be limited to a steady state (cruise) power of about 50%. =20 Of course, being a pusher driver, I think of inlet air speeds in terms = of the speed of the airplane. So does the fact that the inlet is behind = prop give a much higher effective inlet velocity? I've been thinking that = the turbulence in the prop wash would negate a good portion of the extra = mean air velocity because of reduced inlet effectiveness. =20 It will be interesting to know how it works out on a hot day.=20 =20 Great that you have your 20B in the air and working well. =20 Merry Christmas and Happy New Year to all. =20 Al G =20 =20 =20 ------=_NextPart_000_0016_01CA83A8.CE881690 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable <html> <head> <META HTTP-EQUIV=3D"Content-Type" CONTENT=3D"text/html; = charset=3Dus-ascii"> <meta name=3DGenerator content=3D"Microsoft Word 10 (filtered)"> <style> <!-- /* Font Definitions */ @font-face {font-family:Helvetica; panose-1:2 11 5 4 2 2 2 2 2 4;} @font-face {font-family:Tahoma; panose-1:2 11 6 4 3 5 4 4 2 4;} @font-face {font-family:Verdana; panose-1:2 11 6 4 3 5 4 4 2 4;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNormal {margin:0in; margin-bottom:.0001pt; font-size:12.0pt; font-family:"Times New Roman";} a:link, span.MsoHyperlink {color:blue; text-decoration:underline;} a:visited, span.MsoHyperlinkFollowed {color:blue; text-decoration:underline;} span.EmailStyle17 {font-family:Verdana; color:blue; font-weight:normal; font-style:normal; text-decoration:none none;} @page Section1 {size:8.5in 11.0in; margin:1.0in 1.25in 1.0in 1.25in;} div.Section1 {page:Section1;} --> </style> </head> <body lang=3DEN-US link=3Dblue vlink=3Dblue> <div class=3DSection1> <p class=3DMsoNormal style=3D'margin-bottom:12.0pt'><font size=3D2 = color=3Dblue face=3DVerdana><span = style=3D'font-size:11.0pt;font-family:Verdana;color:blue'>Tracy</span></f= ont><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size:11.0pt;font-family:Verdana; color:blue'> wrote:</span></font></p> <div> <div> <div> <div> <div> <div> <div> <div> <div> <p class=3DMsoNormal style=3D'margin-left:.5in'><font size=3D3 = face=3D"Times New Roman"><span style=3D'font-size:12.0pt'>My 5" round inlet for the radiator looks ridiculously small compared to yours but so far it is cooling the 20B = OK. </span></font></p> </div> </div> </div> </div> </div> </div> </div> </div> </div> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>Now that sort of boggles my mind = as it seems to violate the laws of physics. Let’s just take a modest = climb power of, say; 225 hp. At that power, the energy going into the = coolant is about 6000 Btu/min. In order to remove that amount of heat, at = a typical air temp increase of 75 degrees; takes about 4000 cfm air = flow. A 5” dia inlet is 0.14 sq feet, meaning an average inlet velocity = about 29,000 ft/min, or 330 mph. Even at 100 air temp increase (unlikely on a = 90F day) it’s 250 mph. And I’m guessing your climb speed is = half that. Similar math suggests you’d be limited to a steady = state (cruise) power of about 50%.</span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>Of course, being a pusher driver, = I think of inlet air speeds in terms of the speed of the airplane. = So does the fact that the inlet is behind prop give a much higher effective = inlet velocity? I’ve been thinking that the turbulence in the prop = wash would negate a good portion of the extra mean air velocity because of reduced = inlet effectiveness.</span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>It will be interesting to know = how it works out on a hot day. </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>Great that you have your 20B in = the air and working well.</span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>Merry Christmas and Happy New = Year to all.</span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'>Al G</span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> <p class=3DMsoNormal><font size=3D2 color=3Dblue face=3DVerdana><span = style=3D'font-size: 11.0pt;font-family:Verdana;color:blue'> </span></font></p> </div> </body> </html> ------=_NextPart_000_0016_01CA83A8.CE881690--