X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Received: from eastrmmtao105.cox.net ([68.230.240.47] verified) by logan.com (CommuniGate Pro SMTP 5.3c4) with ESMTP id 4034135 for flyrotary@lancaironline.net; Mon, 21 Dec 2009 16:39:32 -0500 Received-SPF: none receiver=logan.com; client-ip=68.230.240.47; envelope-from=tmann@n200lz.com Received: from eastrmimpo01.cox.net ([68.1.16.119]) by eastrmmtao105.cox.net (InterMail vM.8.00.01.00 201-2244-105-20090324) with ESMTP id <20091221213858.RJUE29464.eastrmmtao105.cox.net@eastrmimpo01.cox.net> for ; Mon, 21 Dec 2009 16:38:58 -0500 Received: from testPC ([70.184.217.221]) by eastrmimpo01.cox.net with bizsmtp id Kxey1d0054nBe7202xeykN; Mon, 21 Dec 2009 16:38:58 -0500 X-VR-Score: 0.00 X-Authority-Analysis: v=1.1 cv=OSH592LicKi2+aIpjjLcurvLcTlgRSPLpNzS8VagXAo= c=1 sm=1 a=gg+spYMGC3HMAXU8AuUugQ==:17 a=jNNRDXGdBW4dbL2LmZgA:9 a=TsP6oxBFiNcUuw5savtULko-3SoA:4 a=9Sf5zU13ep1KXCbA:21 a=mfyW5Lvjg4dOHWJQ:21 a=Y2VNeNrzAAAA:8 a=yMhMjlubAAAA:8 a=TW66zc2HAAAA:8 a=SSmOFEACAAAA:8 a=HQ31llbKAAAA:8 a=7vIflwSl1CBGtXFMW80A:9 a=cUbTkKTzoh7v2tOFnKEA:7 a=LpzCDeji2JKYDdPejA6yRPzMPTMA:4 a=gg+spYMGC3HMAXU8AuUugQ==:117 X-CM-Score: 0.00 From: "Thomas Mann" To: "'Rotary motors in aircraft'" References: In-Reply-To: Subject: RE: [FlyRotary] Re: Air Flow Question Date: Mon, 21 Dec 2009 15:39:02 -0600 Message-ID: <008601ca8286$03a7d640$0af782c0$@com> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0087_01CA8253.B90D6640" X-Mailer: Microsoft Office Outlook 12.0 Thread-Index: AcqCfKbUrONlj489SvWnFld5MHydTwABo4kA Content-Language: en-us This is a multi-part message in MIME format. ------=_NextPart_000_0087_01CA8253.B90D6640 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit The numbers I'm looking at are for relation reference only so 180kt inlet speed does not indicate the airspeed of the aircraft (for sake of argument.) I have read that the airspeed needs to be reduced, hence the expansion from a 16 x 3 opening to a core frontal area of 200 sq in.) As a result of the expansion and drop in pressure, I realize that the air that reaches the core will be cooler than the air that enters the inlet. From the radiator to the exhaust I'm looking at reducing to an opening size of approximately 75 sq inches. Based on what I have read this should slow the air down sufficiently to get it closer to a speed where it can absorb the most heat from the core. Some of the speeds I've been quoted have been in the neighborhood of 35 kts. I don't know how accurate those numbers are. The air is expanding to a greater volume after it passes through the radiator and is compressed due to the ducting which is supposed to result in enough thrust gain to cancel out 90+% of the drag created by the scoop. I know that a 180 > 45 is close. I don't know if I could get away with a smaller inlet or if a 4 to one ration is as far as I can push it. T Mann ------=_NextPart_000_0087_01CA8253.B90D6640 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable

The numbers I’m looking at are for relation = reference only so 180kt inlet speed does not indicate the airspeed of the aircraft (for = sake of argument.)

I have read that the airspeed needs to be reduced, hence = the expansion from a 16 x 3 opening to a core frontal area of 200 sq in.) As = a result of the expansion and drop in pressure, I realize that the air = that reaches the core will be cooler than the air that enters the = inlet.

From the radiator to the exhaust I’m looking at = reducing to an opening size of approximately 75 sq inches. Based on what I have = read this should slow the air down sufficiently to get it closer to a speed = where it can absorb the most heat from the core. Some of the speeds I’ve = been quoted have been in the neighborhood of 35 kts. I don’t know how = accurate those numbers are.

The air is expanding to a greater volume after it passes = through the radiator and is compressed due to the ducting which is supposed to = result in enough thrust gain to cancel out 90+% of the drag created by the = scoop.

I know that a 180 > 45 is close. I don’t know if = I could get away with a smaller inlet or if a 4 to one ration is as far as = I can push it.

T Mann

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