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From: "Ed Anderson" <eanderson@carolina.rr.com>
To: "Rotary motors in aircraft" <flyrotary@lancaironline.net>
References: <list-2645491@logan.com>
Subject: Bill Eslick Radiator coolant delta T
Date: Tue, 21 Oct 2003 17:39:28 -0400
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----- Original Message -----=20
From: Bill Eslick=20
To: Rotary motors in aircraft=20
Sent: Tuesday, October 21, 2003 1:18 PM
Subject: [FlyRotary] Re: Radiator coolant delta T
I promised to report my indicated water temps next chance I got. =
Here are some samples:
OAT(F) Delta T (F)
69 23
66 19
68 10
75 14 =20
65 15
75 7
77 12
All figures are in cruise at 8,000 to 10,000 MSL. Last reading =
was in climbout, but not much difference. I really can't explain the =
range of readings, but that is what it read!
=20
Thanks for the data, Bill
I ran it through my model, but did not have your power or fuel =
burn or airspeed. But assuming you were doing approx 140 Indictated air =
speed at altitude and modest power (5200 rpm) my figures shows a delta T =
of 12.27F. If you were running a bit harder the delta T would go up a =
bit. If you were moving faster than 140 indicated at 5200 rpm then it =
would go down a bit.
For climb I assumed 120 Indicated and a minimum of 130HP this =
gave me a delta T of 24F for the radiators. Both figures not too far =
off from what you are reporting.
So the delta T would seem to be dependent on your power setting =
and air speed most of all. The more BTUs of heat you reject into the =
same amount of mass flow, the greater the delta T. However, the faster =
you go the more cooling mass flow you get which appears to help to hold =
down the delta T. =20
In any case, appreciate the data
Ed Anderson
=20
=20
=20
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<DIV>
<DIV><FONT size=3D2><A=20
href=3D"mailto:eanderson@carolina.rr.com"></A></FONT></DIV>----- =
Original Message=20
----- </DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A title=3Dn268bl@charter.net href=3D"mailto:n268bl@charter.net">Bill =
Eslick</A>=20
</DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dflyrotary@lancaironline.net=20
href=3D"mailto:flyrotary@lancaironline.net">Rotary motors in =
aircraft</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Tuesday, October 21, 2003 =
1:18=20
PM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> [FlyRotary] Re: =
Radiator coolant=20
delta T</DIV>
<DIV><BR></DIV>
<TABLE id=3DINCREDIMAINTABLE cellSpacing=3D0 cellPadding=3D2 =
width=3D"100%"=20
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<TD id=3DINCREDITEXTREGION=20
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<DIV>I promised to report my indicated water temps next chance I =
got.=20
Here are some samples:</DIV>
<DIV> </DIV>
<DIV>OAT(F) Delta T =
(F)</DIV>
<DIV>69 =20
23</DIV>
<DIV>66 =20
19</DIV>
<DIV>68 =20
10</DIV>
<DIV>75 =20
14 =
</DIV>
<DIV>65 =20
15</DIV>
<DIV>75 =20
7</DIV>
<DIV>77 =20
12</DIV>
<DIV> </DIV>
<DIV>All figures are in cruise at 8,000 to 10,000 MSL. =
Last=20
reading was in climbout, but not much difference. I really =
can't=20
explain the range of readings, but that is what it read!</DIV>
<DIV><FONT size=3D2> </FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Thanks for the data, Bill</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2> I ran it through my model, but did=20
not have your power or fuel burn or airspeed. But =
assuming=20
you were doing approx 140 Indictated air speed at altitude and =
modest=20
power (5200 rpm) my figures shows a delta T of 12.27F. If =
you were=20
running a bit harder the delta T would go up a bit. If you =
were=20
moving faster than 140 indicated at 5200 rpm then it would go =
down a=20
bit.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>For climb I assumed 120 Indicated and a =
minimum of=20
130HP this gave me a delta T of 24F for the radiators. =
Both=20
figures not too far off from what you are =
reporting.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>So the delta T would seem to be dependent on =
your=20
power setting and air speed most of all. The more BTUs of =
heat you=20
reject into the same amount of mass flow, the greater the =
delta T.=20
However, the faster you go the more cooling mass flow you get =
which=20
appears to help to hold down the delta T. </FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>In any case, appreciate the =
data</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Ed Anderson</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV></TD></TR>
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