Return-Path: Received: from fed1mtao01.cox.net ([68.6.19.244] verified) by logan.com (CommuniGate Pro SMTP 4.1) with ESMTP id 2511136 for flyrotary@lancaironline.net; Mon, 04 Aug 2003 13:29:04 -0400 Received: from BigAl ([68.107.116.221]) by fed1mtao01.cox.net (InterMail vM.5.01.04.05 201-253-122-122-105-20011231) with ESMTP id <20030804172857.QLSH20780.fed1mtao01.cox.net@BigAl> for ; Mon, 4 Aug 2003 13:28:57 -0400 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: Cooling? Date: Mon, 4 Aug 2003 10:29:07 -0700 Message-ID: <000001c35aad$e901d7c0$6400a8c0@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0001_01C35A73.3CA2FFC0" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.4024 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 This is a multi-part message in MIME format. ------=_NextPart_000_0001_01C35A73.3CA2FFC0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit doesn't that formula depend on absolute temperature like kelvin or so? where zero degree is minus 459 degree F or minus 273 Celsius. the ratio of expansion should be something like: inlet air: 20 degree Celsius (68F) or 293 Kelvin outlet air: 50 degree celsius (122F) or 323 Kelvin then 323 over 293 for a change in temperature gives then the Volume change of more like 1.2 there is some additional expansion due to the pressure difference. Regards Marko Marko; You got me there. You're right, it needs to be the ratio of absolute temp. That gives a ratio of inlet to outlet for the 80 F in and 135 F out of about 1.1. Also for the case you give; 323/293 is 1.1; not 1.2, or did you factor in some additional volume change for pressure. Gees .. you mean now I have to go back and rework my rad outlets? Al ------=_NextPart_000_0001_01C35A73.3CA2FFC0 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable

 

 

doesn't that formula depend on absolute = temperature like kelvin or so? where zero degree is minus 459 degree F or minus 273 Celsius.
the ratio of expansion should be something like:
inlet air: 20 degree Celsius (68F) or 293 Kelvin
outlet air: 50 degree celsius (122F) or 323 Kelvin
then
323 over 293 for a change in temperature gives
then the Volume change of more like 1.2

there is some additional expansion due to the = pressure difference.

Regards

Marko

Marko;

You got me there.  You’re = right, it needs to be the ratio of absolute temp.  That gives a ratio of = inlet to outlet for the 80 F in and 135 F out of about 1.1.  Also for the = case you give; 323/293 is 1.1; not 1.2, or did you factor in some additional = volume change for pressure. 

Gees .. you mean now I have to go back = and rework my rad outlets?

Al

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