Return-Path: Received: from [216.52.245.18] (HELO ispwestemail2.mdeinc.com) by logan.com (CommuniGate Pro SMTP 4.3c1) with ESMTP id 722675 for flyrotary@lancaironline.net; Wed, 09 Feb 2005 16:45:43 -0500 Received-SPF: none receiver=logan.com; client-ip=216.52.245.18; envelope-from=wschertz@ispwest.com Received: from 7n7z201 (unverified [67.136.145.222]) by ispwestemail2.mdeinc.com (Vircom SMTPRS 4.0.340.3) with SMTP id for ; Mon, 7 Feb 2005 17:12:55 -0800 Message-ID: <00c001c50d7b$48507ca0$d6918843@7n7z201> From: "William" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Heating the Fuel Date: Mon, 7 Feb 2005 19:12:36 -0600 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_00BD_01C50D48.FC242200" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2180 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_00BD_01C50D48.FC242200 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable [FlyRotary] Re: Performance coatings- bearing damage?Dave, If you burn 10 g/hr, and are returning 15 g/hr to the tanks, that is = 15*6 =3D 90 #/hr of gasoline, with a specific heat of ~.7Btu/#, that = means you can transfer 90* 0.7 =3D 63 Btu/hr/degF rise in gasoline = temperature. Your coolant flow is probably about 25 gallons/minute, =3D = 25*60 =3D 1500 gallons/hour =3D ~1500*8 =3D 12000 #/hour. For a 10 = degree rise in gasoline temperature you would get a 630/12000 =3D 0.0525 = deg F drop in coolant temperature. Doesn't seem worth it. * note: I used rounded figures for densities and flow rates and heat = capacities. The fact remains that the flow mismatch makes this not do = much. Bill Schertz KIS Cruiser # 4045 ----- Original Message -----=20 From: DaveLeonard=20 To: Rotary motors in aircraft=20 Sent: Sunday, February 06, 2005 11:46 PM Subject: [FlyRotary] Heating the Fuel In anticipation of the new turbo, I am considering ways to improve = coolant cooling. Besides the obvious more air, more ducting, more = radiator; I have been again toying with the idea of a heat exchanger. = This time coolant to fuel. The plan would be to use a typical oil/water = exchanger but use fuel instead of oil. I would use the fuel on the way = back to the tank, and the coolant after it has already been cooled by = the radiator. The fuel would then go back to the nice metal tank of the = RV. I am looking for input on the implications of heating the fuel. I = expect it would reach max temps of about 190 (usually a little cooler) = but quickly cool once in the tank. Can the fuel tolerate that temp = without vaporizing? It will probably expand in the tank but I don't = expect that will occur faster than it is used up. I have no guess as to = what temp will become steady state for the fuel pumped out of the tank. = My guess is that it will not be much warmer than normal, but a slight = increase in temp may help with vaporization. The last question is how much will it cool the coolant. My hope is = about 10 deg but I doubt it will be quite that much. I know others have = considered using the fuel to cool (Tracy) and I would appreciate your = thoughts. Dave Leonard ------=_NextPart_000_00BD_01C50D48.FC242200 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable [FlyRotary] Re: Performance coatings- bearing = damage?
Dave,
If you burn 10 g/hr, and are returning = 15 g/hr to=20 the tanks, that is 15*6 =3D 90 #/hr of gasoline, with a specific heat of = ~.7Btu/#,=20 that means you can transfer 90* 0.7 =3D 63 Btu/hr/degF rise in gasoline=20 temperature. Your coolant flow is probably about 25 gallons/minute, =3D = 25*60 =3D=20 1500 gallons/hour =3D ~1500*8 =3D 12000 #/hour. For a 10 degree = rise in=20 gasoline temperature you would get a 630/12000 =3D 0.0525 deg F drop in = coolant=20 temperature.  Doesn't seem worth it.
 
* note: I used rounded figures for = densities and=20 flow rates and heat capacities. The fact remains that the flow mismatch = makes=20 this not do much.
Bill Schertz
KIS Cruiser # 4045
----- Original Message -----
From:=20 DaveLeonard=20
Sent: Sunday, February 06, 2005 = 11:46=20 PM
Subject: [FlyRotary] Heating = the=20 Fuel

In=20 anticipation of the new turbo, I am considering ways to improve = coolant=20 cooling.  Besides the obvious more air, more ducting, more = radiator; I=20 have been again toying with the idea of a heat exchanger.  This = time=20 coolant to fuel.  The plan would be to use a typical oil/water = exchanger=20 but use fuel instead of oil.  I would use the fuel on the way = back to the=20 tank, and the coolant after it has already been cooled by the = radiator. =20 The fuel would then go back to the nice metal tank of the=20 RV.
 
I am=20 looking for input on the implications of heating the fuel.  I = expect it=20 would reach max temps of about 190 (usually a = little cooler) but=20 quickly cool once in the tank.  Can the fuel tolerate that temp = without=20 vaporizing?  It will probably expand in the tank but I don't = expect that=20 will occur faster than it is used up.  I have no guess as to what = temp=20 will become steady state for the fuel pumped out of the tank.  My = guess=20 is that it will not be much warmer than normal, but a slight increase = in temp=20 may help with vaporization.
 
The=20 last question is how much will it cool the coolant.  My hope is = about 10=20 deg but I doubt it will be quite that much.  I know others have=20 considered using the fuel to cool (Tracy) and I would appreciate your=20 thoughts.
 
Dave=20 Leonard
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