X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Fri, 10 Feb 2012 14:38:11 -0500 Message-ID: X-Original-Return-Path: Received: from imr-ma01.mx.aol.com ([64.12.206.39] verified) by logan.com (CommuniGate Pro SMTP 5.4.4) with ESMTP id 5390825 for lml@lancaironline.net; Fri, 10 Feb 2012 10:38:59 -0500 Received-SPF: pass receiver=logan.com; client-ip=64.12.206.39; envelope-from=Sky2high@aol.com Received: from mtaomg-db05.r1000.mx.aol.com (mtaomg-db05.r1000.mx.aol.com [172.29.51.203]) by imr-ma01.mx.aol.com (8.14.1/8.14.1) with ESMTP id q1AFcHdP031621 for ; Fri, 10 Feb 2012 10:38:17 -0500 Received: from core-mtc005a.r1000.mail.aol.com (core-mtc005.r1000.mail.aol.com [172.29.235.17]) by mtaomg-db05.r1000.mx.aol.com (OMAG/Core Interface) with ESMTP id E9086E000086 for ; Fri, 10 Feb 2012 10:38:16 -0500 (EST) From: Sky2high@aol.com X-Original-Message-ID: <25f78.3d7b8bd.3c6693e8@aol.com> X-Original-Date: Fri, 10 Feb 2012 10:38:16 -0500 (EST) Subject: Re: [LML] Legacy Flap Symmetry Question X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="part1_25f78.3d7b8bd.3c6693e8_boundary" X-Mailer: AOL 9.6 sub 168 X-Originating-IP: [67.175.156.123] x-aol-global-disposition: G X-AOL-SCOLL-SCORE: 0:2:392292640:93952408 X-AOL-SCOLL-URL_COUNT: 0 x-aol-sid: 3039ac1d33cb4f3539e803b2 --part1_25f78.3d7b8bd.3c6693e8_boundary Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Content-Language: en Stan, =20 Adjust the rigging so that the deployment angles are as close as possible.= =20 You will find that further adjustment may be necessary while you are in= =20 the test flying phase of the airworthiness certification. I.E. A wing may= =20 seem inordinately "heavy" and adjusting the flap rigging may correct that= =20 condition (one side up a half turn on the bearing and the other down a hal= f=20 turn). =20 Scott Krueger =20 =20 In a message dated 2/10/2012 9:28:30 A.M. Central Standard Time, =20 sdfields@austin.rr.com writes: =20 I=E2=80=99m building in my garage so I usually work one side of the plane = then the=20 other. So far that has worked well. However, I installed my left Flap and= =20 adjusted the control rod to produce a 0-40 degree movement. I hooked it to= =20 the Flap actuator to produce these limits and everything was perfect.=20 Now I have attached the right Flap and adjusted the control rod to align= =20 with the aileron Unfortunately the Flap actuator produces a 41.8 degree=20 movement. I can=E2=80=99t see how to change this without customizing the Fl= ap =20 installation in some way.=20 So, how much difference will 1.8 degree difference make in flight=20 characteristics at full deployment. Has anyone experienced this and what d= id you=20 do?=20 Stan Fields=20 L2K #201 --part1_25f78.3d7b8bd.3c6693e8_boundary Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Content-Language: en

Stan,

Adjust the rigging so that the deployment angles are as close as=20 possible. You will find that further adjustment may be necessary whil= e you=20 are in the test flying phase of the airworthiness certification. = =20 I.E. A wing may seem inordinately "heavy" and adjusting the flap riggi= ng=20 may correct that condition (one side up a half turn on the bearing and the = other=20 down a half turn).

Scott Krueger

In a message dated 2/10/2012 9:28:30 A.M. Central Standard Time,=20 sdfields@austin.rr.com writes:

I=E2=80=99m building in my garage so I usually work = one side of the=20 plane then the other. So far that has worked well. However, I installed m= y=20 left Flap and adjusted the control rod to produce a 0-40 degree movement.= I=20 hooked it to the Flap actuator to produce these limits and everything was= =20 perfect.

Now I have attached the right Flap and adjusted the = control=20 rod to align with the aileron Unfortunately the Flap actuator produces a = 41.8=20 degree movement. I can=E2=80=99t see how to change this without customizi= ng the Flap=20 installation in some way.

So, how much difference will 1.8 degree difference m= ake in=20 flight characteristics at full deployment. Has anyone experienced this an= d=20 what did you do?

Stan Fields

L2K=20 #201

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