X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Mon, 09 Aug 2010 15:04:51 -0400 Message-ID: X-Original-Return-Path: Received: from hrndva-omtalb.mail.rr.com ([71.74.56.125] verified) by logan.com (CommuniGate Pro SMTP 5.3.8) with ESMTP id 4423718 for lml@lancaironline.net; Mon, 09 Aug 2010 10:21:10 -0400 Received-SPF: none receiver=logan.com; client-ip=71.74.56.125; envelope-from=Wolfgang@MiCom.net X-Original-Return-Path: X-Authority-Analysis: v=1.1 cv=puNM1lMKksHKE6hmMqMstpyRmqXf+M/teYaxpNq+S3U= c=1 sm=0 a=MHZY6FYWMEQOp7S43i2QIw==:17 a=Ia-xEzejAAAA:8 a=ndVRne3UAAAA:8 a=rTjvlri0AAAA:8 a=sfhgc42sc1MgmulS08wA:9 a=cYJS_GkwNxNF80Uxk1m8kotOsTwA:4 a=wPNLvfGTeEIA:10 a=ILeVjEvywfEA:10 a=EzXvWhQp4_cA:10 a=Dr9Wx-Q63l4A:10 a=CjxXgO3LAAAA:8 a=DASxfYdEG-_C6USvR0oA:9 a=d9oFDzdFMPCYe30YYNcA:7 a=5sxR16fOV0mjtFLgjKSH6lYS3nkA:4 a=rC2wZJ5BpNYA:10 a=MHZY6FYWMEQOp7S43i2QIw==:117 X-Cloudmark-Score: 0 X-Originating-IP: 74.218.201.50 Received: from [74.218.201.50] ([74.218.201.50:1101] helo=Lobo) by hrndva-oedge04.mail.rr.com (envelope-from ) (ecelerity 2.2.2.39 r()) with ESMTP id B3/5F-24046-1BE006C4; Mon, 09 Aug 2010 14:20:33 +0000 X-Original-Message-ID: <002f01cb37ce$0031de90$6401a8c0@Lobo> From: "Wolfgang" X-Original-To: References: Subject: Re: [LML] Re: flap coupling X-Original-Date: Mon, 9 Aug 2010 10:20:21 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_002C_01CB37AC.78DFDA30" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2180 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_002C_01CB37AC.78DFDA30 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Can you give some detail on that one ? How can that be ? Wolfgang ----- Original Message -----=20 From: Chris Zavatson=20 To: lml@lancaironline.net=20 Sent: Sunday, August 08, 2010 7:46 PM Subject: Re: [LML] Re: flap coupling The MKII tail is a little different. Push rod forces are zero for all = trimmed conditions. Chris Zavatson =20 N91CZ =20 360std www.N91CZ.com =20 -------------------------------------------------------------------------= ----- From: Wolfgang To: lml@lancaironline.net Sent: Fri, August 6, 2010 10:06:44 PM Subject: [LML] Re: flap coupling I have taken elevator pushrod force measurements and was surprised. Elevator pushrod forces to stick forces are about 6.5 to 1 The trim system, when dialed in, provides these forces. At 190 imph and -7=BA flaps, there is a 60lb forward force. At 80 imph and 10=BA flaps, there is about zero force. At 80 imph and 20=BA flaps, there is a slight (-1lb) rearward force. These numbers are with the horizontal stabilizer built at -1.2=BA - - - plans range is -0.5=BA to -1.0=BA An input from the flap bellcrank of about 20-40 lb at -7=BA would be = good, tapering down to zero lbs at 10=BA flaps A horizontal stabilizer built at -0.5=BA would, of course, change = these numbers. Comments ? Wolfgang ------=_NextPart_000_002C_01CB37AC.78DFDA30 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Can you give some detail on that one = ?
How can that be ?
 
Wolfgang
 
----- Original Message -----
From:=20 Chris=20 Zavatson
Sent: Sunday, August 08, 2010 = 7:46=20 PM
Subject: Re: [LML] Re: flap=20 coupling

The MKII tail is a little different.  Push rod forces = are zero=20 for all trimmed conditions.
 
Chris Zavatson   
N91CZ   
360std

 

From: Wolfgang <Wolfgang@MiCom.net>
To: lml@lancaironline.net
Sent: Fri, August 6, 2010 = 10:06:44=20 PM
Subject: [LML] = Re: flap=20 coupling

I have taken elevator pushrod force = measurements=20 and was surprised.
Elevator pushrod forces to stick = forces are about=20 6.5 to 1
The trim system, when dialed in, = provides these=20 forces.
 
At 190 imph and -7=BA flaps, = there is a 60lb=20 forward force.
At 80 imph and 10=BA flaps, there is = about zero=20 force.
At 80 imph and 20=BA flaps, there is = a slight=20 (-1lb) rearward force.
 
These numbers are with the horizontal = stabilizer=20 built at -1.2=BA
- - - plans range is -0.5=BA to = -1.0=BA
 
An input from the flap bellcrank = of about=20 20-40 lb at -7=BA would be good,
 tapering down to zero lbs at = 10=BA=20 flaps
 
A horizontal stabilizer built at = -0.5=BA would, of=20 course, change these numbers.
 
Comments ?
 
Wolfgang
 

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