X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Wed, 04 Jul 2007 09:20:02 -0400 Message-ID: X-Original-Return-Path: Received: from elasmtp-dupuy.atl.sa.earthlink.net ([209.86.89.62] verified) by logan.com (CommuniGate Pro SMTP 5.1.10) with ESMTP id 2157716 for lml@lancaironline.net; Wed, 04 Jul 2007 09:08:27 -0400 Received-SPF: none receiver=logan.com; client-ip=209.86.89.62; envelope-from=matt.hapgood@alumni.duke.edu Received: from [65.40.217.234] (helo=aprilia.hapgoods.com) by elasmtp-dupuy.atl.sa.earthlink.net with asmtp (TLSv1:AES256-SHA:256) (Exim 4.34) id 1I64aD-0004To-Qp for lml@lancaironline.net; Wed, 04 Jul 2007 09:07:50 -0400 Received: from HappyMotion (c-76-19-206-249.hsd1.ma.comcast.net [76.19.206.249]) (authenticated bits=0) by aprilia.hapgoods.com (8.13.8/8.13.8) with ESMTP id l64D7ACo014530 (version=TLSv1/SSLv3 cipher=RC4-MD5 bits=128 verify=NO) for ; Wed, 4 Jul 2007 09:07:48 -0400 From: "Matt Hapgood" X-Original-To: "'Lancair Mailing List'" References: In-Reply-To: Subject: RE: [LML] Re: FW: [LML] Re: ADAHRS TSO X-Original-Date: Wed, 4 Jul 2007 09:07:20 -0400 X-Original-Message-ID: <016801c7be3c$58982670$09c87350$@hapgood@alumni.duke.edu> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0169_01C7BE1A.D1868670" X-Mailer: Microsoft Office Outlook 12.0 thread-index: Ace9xOn5YqfMmH+tQYaIwEcc5ssPGQAJ/U6w Content-Language: en-us X-ELNK-Trace: b48a86202a850ddb74bf435c0eb9d47825234a3a243c1acbc5a254678f30974b693077083a6f95a5350badd9bab72f9c350badd9bab72f9c350badd9bab72f9c X-Originating-IP: 65.40.217.234 This is a multipart message in MIME format. ------=_NextPart_000_0169_01C7BE1A.D1868670 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit Close. I think it is 4: One side of beam/other side of beam/leftover 13/13/1 6/6/1 3/3 1/1/1 From: Lancair Mailing List [mailto:lml@lancaironline.net] On Behalf Of marv@lancair.net Sent: Tuesday, July 03, 2007 6:53 PM To: lml@lancaironline.net Subject: [LML] Re: FW: [LML] Re: ADAHRS TSO Posted for "John Barrett" <2thman@cablespeed.com>: Let me try that again. If you are lucky just weigh one. If it's the heavy one, then you've done it in one measurement - that's the answer to the question. Assuming you are unlucky and need to find the quickest path of eliminating the 623 gram cylinders, Then I think the number of steps is five. It is conditional, but either path requires five measurements to get to one remaining piston. You would pick groups of cylinders to weigh in one of the following two sequences: 1. 13,6,3,2,1 2. 13,7,4,2,1 Obviously, you would select each group by halving or halving minus one piston (even or odd group?) from each succeeding "heavy". Just divide the weight of each sample by 623. If there is one gram left over, then the next halving should be taken randomly fr om that group. Otherwise, grab from the pistons you randomly did not select to do the most current weighing. -- For archives and unsub http://mail.lancaironline.net:81/lists/lml/List.html ------=_NextPart_000_0169_01C7BE1A.D1868670 Content-Type: text/html; charset="us-ascii" Content-Transfer-Encoding: quoted-printable

Close. I think it is 4:

One side of beam/other side of = beam/leftover

13/13/1

6/6/1

3/3

1/1/1

From:= Lancair = Mailing List [mailto:lml@lancaironline.net] On Behalf Of = marv@lancair.net
Sent: Tuesday, July 03, 2007 6:53 PM
To: lml@lancaironline.net
Subject: [LML] Re: FW: [LML] Re: ADAHRS TSO

Posted for "John Barrett" <2thman@cablespeed.com>:

Let me try that again. If you are lucky just weigh one. If it’s = the heavy
one, then you’ve done it in one measurement – that’s = the answer to the
question.

Assuming you are unlucky and need to find the quickest path of = eliminating
the 623 gram cylinders, Then I think the number of steps is five. It = is
conditional, but either path requires five measurements to get to = one
remaining piston. You would pick groups of cylinders to weigh in one of = the
following two sequences:

1. 13,6,3,2,1
2. 13,7,4,2,1

Obviously, you would select each group by halving or halving minus = one
piston (even or odd group?) from each succeeding “heavy”. = Just divide the
weight of each sample by 623. If there is one gram left over, then the = next
halving should be taken randomly fr om that group. Otherwise, grab from = the
pistons you randomly did not select to do the most current = weighing.

--

For archives =
and unsub =
http://mail.lancaironline.net:81/lists/lml/List.html

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