X-Virus-Scanned: clean according to Sophos on Logan.com X-SpamCatcher-Score: 30 [X] Return-Path: Sender: To: lml@lancaironline.net Date: Sat, 12 May 2007 12:25:43 -0400 Message-ID: X-Original-Return-Path: Received: from elasmtp-masked.atl.sa.earthlink.net ([209.86.89.68] verified) by logan.com (CommuniGate Pro SMTP 5.1.8) with ESMTP id 2039775 for lml@lancaironline.net; Sat, 12 May 2007 10:23:43 -0400 Received-SPF: none receiver=logan.com; client-ip=209.86.89.68; envelope-from=rtitsworth@mindspring.com DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=dk20050327; d=mindspring.com; b=UaDxlW/j7WXI+Gv8Zt0QbdP+CFZcIXKcIpldTPYo8ej5i2tAv3Ik3gDd8AE6hWEA; h=Received:From:To:Subject:Date:Message-ID:MIME-Version:Content-Type:Content-Transfer-Encoding:X-Mailer:Thread-Index:In-Reply-To:X-MimeOLE:X-ELNK-Trace:X-Originating-IP; Received: from [66.167.211.142] (helo=RDTVAIO) by elasmtp-masked.atl.sa.earthlink.net with asmtp (Exim 4.34) id 1HmsOQ-0003Ie-7n for lml@lancaironline.net; Sat, 12 May 2007 10:16:18 -0400 From: "rtitsworth" X-Original-To: "'Lancair Mailing List'" Subject: RE: [LML] Flight Characteristic Question X-Original-Date: Sat, 12 May 2007 10:15:52 -0400 X-Original-Message-ID: <000001c794a0$0c578910$84affea9@RDTVAIO> MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit X-Mailer: Microsoft Office Outlook 11 Thread-Index: AceUOBeyg1Ww0WgCQAWxka87mP74JgAZLYEg In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.3028 X-ELNK-Trace: b17f11247b2ac8f0a79dc4b33984cbaa0a9da525759e26542daf4f4b637de960485aa68db39badaba30146a21c727840350badd9bab72f9c350badd9bab72f9c X-Originating-IP: 66.167.211.142 My understanding (some please correct me if wrong/misleading)... In the end (i.e. in-flight), the "overall" incidence is ultimately controlled by the position of the elevator (i.e. the actual trailing edge). Thus, if you get the horizontal stabilizer incidence exactly "correct", then the elevator will be straight entrail. However, this situation only holds for a specific speed and W&B combination. At other speed and W&B combinations, you'll need some up/down elevator position (trim) to maintain level flight. One would guess that the Lancair/factory recommended horizontal stab incidence setting is correct for the center of the operating envelope (normal cruise?). In approximate terms, if you had the horizontal "off" by 1/2 degree (up or down), then you'll be flying with the elevator "off" in the other direction by a corresponding amount (perhaps approx twice the degree measurement due to the shorter chord/arm). The elevator would still likely be perfectly entrail at some speed/weight combination, but perhaps not in normal cruise. A bad scenario is that you have the horizontal so far "off" (leading edge up) that you run out of up elevator movement in the flare. The other bad scenario is that the horizontal is so far "off" (leading edge down) that you need "lots" of down elevator at high speeds (added drag). -----Original Message----- From: Lancair Mailing List [mailto:lml@lancaironline.net] On Behalf Of Bryan Wullner Sent: Friday, May 11, 2007 9:51 PM To: lml@lancaironline.net Subject: [LML] Flight Characteristic Question I am building a Lancair 360. I just permanently bonded the Horizontal stab on. I took every precaution to get it within the 1/2 to 1 degree of negative incidence that Lancair specifies. I used the water level to come come up with the proper incidence based on the plans. After cure I recheck my incidence and Im 99% sure I have somewhere between .09 and 1.3 degree of negative incidence My question is: If the Horizontal has more than 1 degree of Negative incidence, say 1.5 or higher, how does that affect the flight characteristics? And vice versa if it doesn't have enough negative incidence what does that do to the flight? Thanks Bryan -- For archives and unsub http://mail.lancaironline.net:81/lists/lml/List.html