Mailing List lml@lancaironline.net Message #35984
From: Paul Lipps <elippse@sbcglobal.net>
Sender: <marv@lancaironline.net>
Subject: Descent vs bank angle
Date: Thu, 18 May 2006 18:02:27 -0400
To: <lml@lancaironline.net>

I couldn't open the attachment myself on LML so here it is:

Here’re some ruminations for the mathematically-inclined to look over and add any corrections they deem necessary. I tried to solve for the power-off rate-of-descent and altitude loss at three different bank angles, 30° , 45° , and 60° . I used the parameters of my 235 with me and 30 gallons: W-1400 lb, S-24.9’, A-78 sq.ft., VY-110 mph IAS, Î , Oswald efficiency factor, 0.82*. At VY, best L/D, induced drag, DI, and parasite drag, DP, are equal.

V ft/s= 22mph/15, r =2.37689E-3, Q=r V2/2, CL=W/QA, AR=S2/A, DP= QAPD CDI=CL2/p ARÎ =W2/Q2Ap Î S2 DI=QACDI=W2/Qp Î S2=DP APD=DP/Q

Even though we would not be flying at sea-level, using sea-level values simplifies the calculations for this mathematical exercise.

Using my VY and my plane’s parameters, Q=30.93 at VY so APD=1.282

Assuming that APD is a constant, we can rearrange terms and solve for V2 with different values of g-load-multiplied weight.

V2=2gW/r S(p Î APD)½ This may be simplified to V=(26033g)½

In circular flight at a bank angle of Q , the g load is 1/cosQ and the centripetal force, CF, g units,=tanQ = V2/g0r, where g0=32.16, so radius r=V2/CFg0

Multiplying the obtained radius by p to get the 180° turn circumference, then dividing this by V we get the time t for the turn. Since the total drag is twice the parasite drag or induced drag, HP=2QAPDV. The rate of descent to give the required HP, VS=550HP/W, ft/sec.

So for bank angles of 30° , 45° , and 60° , the following values were obtained:

g: 1.155,1.414, 2.0; IAS mph: 118.2,130.7,155.5; radius ft.: 1618.6, 1142.6, 933.8; t sec.: 29.33, 18.73, 12.86; drag lb.: 80.43, 112.5, 159.1; HP: 25.34, 39.23, 65.99; VS ft/sec: 9.955, 15.41, 25.92; Alt. Loss: 292‘, 289‘, 333‘.

It appears there may be an optimum bank angle of 45° that gives the minimum loss of altitude. I’ve heard that is what sailplane pilots use. Now the altitude loss figures do not account for the loss entering the descent nor the loss during recovery, but the higher bank angle turns result in less distance away from the runway, which has some merit. Food for thought!

*Î is 0.75+ for square tips with rounded edges, 0.75- for rounded-planform tips, 0.80 for Hoerner tips with sharp edges, 0.81 for square tips with sharp edges (Mooney), and 0.82 for raked tips with sharp edges (mine).

Subscribe (FEED) Subscribe (DIGEST) Subscribe (INDEX) Unsubscribe Mail to Listmaster