From: RWolf99@aol.com
Message-ID: <0.88c4e4dc.25338d73@aol.com>
Date: Mon, 11 Oct 1999 14:58:59 EDT
Subject: Pitot tube (dynamic) pressure
To: lancair.list@olsusa.com
Mime-Version: 1.0

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In a message dated 10/10/99 9:58:21 PM, you wrote:

<<The relationship between air velocity and pitot pressure is as follows:
        H = V^2/(2*g)  
I don't have the texts handy, but pretty sure this is about right.  The 
relationship is out of the fluid flow book.>>

Sorry, but I have to disagree.

My fluid flow textbooks say that dynamic pressure is one-half times air 
density time velocity squared.

P = 1/2 * rho * V^2

where rho is air density and V is velocity.  If you use rho = 0.002378 slugs 
per cubic foot (sea level standard) and velocity in feet per second, you get 
P (dynamic pressure) in pounds per square foot.  Divide the result by 144 to 
get PSI.
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