X-Virus-Scanned: clean according to Sophos on Logan.com Return-Path: Sender: To: lml@lancaironline.net Date: Thu, 29 Dec 2005 11:00:57 -0500 Message-ID: X-Original-Return-Path: Received: from imo-m17.mx.aol.com ([64.12.138.207] verified) by logan.com (CommuniGate Pro SMTP 5.0.5) with ESMTP id 905128 for lml@lancaironline.net; Thu, 29 Dec 2005 10:26:50 -0500 Received-SPF: pass receiver=logan.com; client-ip=64.12.138.207; envelope-from=MikeEasley@aol.com Received: from MikeEasley@aol.com by imo-m17.mx.aol.com (mail_out_v38_r6.3.) id q.257.3f94270 (57365) for ; Thu, 29 Dec 2005 10:26:03 -0500 (EST) From: MikeEasley@aol.com X-Original-Message-ID: <257.3f94270.30e55a0b@aol.com> X-Original-Date: Thu, 29 Dec 2005 10:26:03 EST Subject: Re: [LML] Re: N320WH Destroyed, No Injuries, idle power descent? X-Original-To: lml@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1135869963" X-Mailer: 9.0 Security Edition for Windows sub 5300 X-Spam-Flag: NO -------------------------------1135869963 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit George, How difficult is it to figure out what the fuel/air ratio would be at 15,500 at 50 LOP and see what happens when you change the air, leaving the fuel alone. I can't imagine (with my simple mind) that an engine could run at SL on that much fuel, with all that extra air. Can that be calculated? Mike Easley -------------------------------1135869963 Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable

George,

How difficult is it to figure out what the fuel/air ratio would be at=20 15,500 at 50 LOP and see what happens when you change the air, leaving the f= uel=20 alone. I can't imagine (with my simple mind) that an engine could run=20= at=20 SL on that much fuel, with all that extra air. Can that be=20 calculated?

Mike Easley

-------------------------------1135869963--