In a message dated 12/13/2005 10:16:18 P.M. Central Standard Time,
N4ZQ@comcast.net writes:
The
K&N filter people say their filter material is designed to pass
air at the rate of 6cf/min so it's relatively easy to calculate the
filter area and end up with a cfm rating for the filter. Now, the
question is... how does one equate lbs/hr to cfm in order to come up
with the right size filter?
Try this,
Your engine is an air pump. For a 4 cylinder aircraft engine each
revolution has 1 cylinder drawing in air, 1 compressing air, 1 firing and 1
exhausting combustion products. Thus, 1 revolution consumes 1/4 x 360
cubic inches or 90 ci or .625 cubic feet. At 2700 rpm and WOT, that's 2700 x
.675 cf or 1688 cfm. Lbs/Hr depends on air density.
K&N has a formula for size:
filter area = (CI x RPM)/20839
filter area = (360 x 2700)/20839 = 47 square inches of effective filter
area, add .75" to each dimension for actual since air doesn't flow well at the
edge of the filter.
Scott Krueger
AKA Grayhawk
Lancair N92EX IO320 SB 89/96
Aurora, IL (KARR)
Merry
Christmas to all!