Return-Path: Received: from [65.54.169.185] (HELO hotmail.com) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP id 2992522 for flyrotary@lancaironline.net; Sat, 14 Feb 2004 21:42:12 -0500 Received: from mail pickup service by hotmail.com with Microsoft SMTPSVC; Sat, 14 Feb 2004 18:42:07 -0800 Received: from 67.25.26.223 by bay3-dav155.bay3.hotmail.com with DAV; Sun, 15 Feb 2004 02:42:07 +0000 X-Originating-IP: [67.25.26.223] X-Originating-Email: [kerrjb@msn.com] X-Sender: kerrjb@msn.com From: "WALTER KERR" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] Re: EFI Fuel Pressurek(column pressure) Date: Sat, 14 Feb 2004 17:05:43 -0500 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0072_01C3F31C.C8EE4C40" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: MSN 8.5 X-MimeOLE: Produced By MSN MimeOLE V8.50.0017.1202 Seal-Send-Time: Sat, 14 Feb 2004 17:05:45 -0500 Message-ID: X-OriginalArrivalTime: 15 Feb 2004 02:42:07.0937 (UTC) FILETIME=[4DD62310:01C3F36D] This is a multi-part message in MIME format. ------=_NextPart_000_0072_01C3F31C.C8EE4C40 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I first ran into this too many years ago in engineering statics. A head = or column of liquid exerts a pressure per unit area only dependant on = how high the column and the density of the liquid. No calculus involved = to calculate the pressure at the bottom if the density can be considered = incompressible such as fuel or water, but not air if the column is very = tall. Now if we wish to calculate the total force on a dam or a = container that has a vertical component, then we need calculus to be = able compute the force. Do not have a neat analogy at the moment to = explain it better. One thing that grabbed me was to calculate the force exerted on a dam is = that you only need the dimensions of the dam and density of the liquid, = ie it is independent of how far or how much water is backed. If we build a dam that backs a tremendous amount of water and now build = a second dam just upstream of it, the force on the first one will not = feel any change. Now if we pump all the water from upstream of the 2nd = dam, the downstream or original dam will still not feel any difference, = but the 2nd dam will now feel the same force in the opposite direction. = Hope this might clear the muddy water a little :>) Back to original question of where to dump the return fuel. I doubt if = the pressure at the fuel injection point will be changed as a function = of where you put it back in the tank. This assumes the regulator does = not hit a limit of travel. Bernie Kerr, 6A sold :>( Hopefully 9A rotary flying soon. ----- Original Message -----=20 From: Bob Darrah=20 To: Rotary motors in aircraft=20 Sent: Friday, February 13, 2004 6:23 PM Subject: [FlyRotary] Re: EFI Fuel Pressure ----- Original Message ----- From: To: "Rotary motors in aircraft" Sent: Friday, February 13, 2004 3:29 PM Subject: [FlyRotary] Re: EFI Fuel Pressure Snip > Actually, the rest of the feul will exert some extra force on the = column, but it requires calculus to figure it out and it won't be much. > I must have been playing hooky the day they taught that. Could you = explain that just a little more? It doesn't correspond to my learnin and experience. Bob Darrah >> Homepage: http://www.flyrotary.com/ >> Archive: http://lancaironline.net/lists/flyrotary/List.html ------=_NextPart_000_0072_01C3F31C.C8EE4C40 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
I first ran into this too many years ago in engineering statics. A = head or=20 column of liquid exerts  a  pressure per unit area only=20 dependant on how high the column and the density of the = liquid. No=20 calculus involved to calculate the pressure at the bottom if the density = can be=20 considered incompressible such as fuel or water, but not air if the = column is=20 very tall. Now if we wish to calculate the total force on a dam or a = container=20 that has a vertical component, then we need calculus to be able compute = the=20 force. Do not have a neat analogy at the moment to explain it = better.
 
One thing that grabbed me was to calculate the force exerted on a = dam is=20 that you only need the dimensions of the dam and density of the liquid, = ie it is=20 independent of how far or how much water is backed.
 
If we build a dam that backs a tremendous amount of water and now = build a=20 second dam just upstream of it, the force on the first one will not feel = any=20 change. Now if we pump all the water from upstream of the 2nd dam, the=20 downstream or original dam will still not feel any difference, but = the 2nd=20 dam will now feel the same force in the opposite direction. Hope this = might=20 clear the muddy water a little :>)
 
Back to original question of where to dump the return fuel. I doubt = if the=20 pressure at the fuel injection point will be changed as a function of = where you=20 put it back in the tank. This assumes the regulator does not hit a limit = of=20 travel.
 
Bernie Kerr, 6A sold :>(  Hopefully 9A rotary flying = soon.
----- Original Message -----
From: Bob Darrah
To: Rotary motors in = aircraft
Sent: Friday, February 13, 2004 = 6:23=20 PM
Subject: [FlyRotary] Re: EFI = Fuel=20 Pressure


----- Original Message -----
From: <echristley@nc.rr.com>
To: = "Rotary=20 motors in aircraft" <flyrotary@lancaironline.net>
Sent:=20 Friday, February 13, 2004 3:29 PM
Subject: [FlyRotary] Re: EFI Fuel = Pressure

Snip
> Actually, the rest of the feul will exert = some=20 extra force on the column,
but it requires calculus to figure it = out and it=20 won't be much.
>

I must have been playing hooky the day = they=20 taught that.  Could you explain
that just a little more?  = It=20 doesn't correspond to my learnin and
experience.

Bob=20 Darrah



>>  Homepage:  http://www.flyrotary.com/
>&= gt; =20 Archive:   http://lancai= ronline.net/lists/flyrotary/List.html
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