Return-Path: Sender: (Marvin Kaye) To: flyrotary@lancaironline.net Date: Thu, 05 Feb 2004 08:52:47 -0500 Message-ID: X-Original-Return-Path: Received: from wb2-a.mail.utexas.edu ([128.83.126.136] verified) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP-TLS id 2976815 for flyrotary@lancaironline.net; Thu, 05 Feb 2004 08:43:03 -0500 Received: (qmail 81243 invoked from network); 5 Feb 2004 13:43:02 -0000 Received: from dhcp-191-101.per.utexas.edu (HELO benefits3.mail.utexas.edu) (146.6.191.101) by wb2.mail.utexas.edu with RC4-SHA encrypted SMTP; 5 Feb 2004 13:43:02 -0000 X-Original-Message-Id: <5.1.1.5.2.20040205073937.024c7970@localhost> X-Sender: msteitle@mail.utexas.edu@localhost X-Mailer: QUALCOMM Windows Eudora Version 5.1.1 X-Original-Date: Thu, 05 Feb 2004 07:42:56 -0600 X-Original-To: "Rotary motors in aircraft" From: Mark Steitle Subject: Re: [FlyRotary] Re: air flow, induction air scoop In-Reply-To: Mime-Version: 1.0 Content-Type: multipart/alternative; boundary="=====================_54871000==.ALT" --=====================_54871000==.ALT Content-Type: text/plain; charset="us-ascii"; format=flowed At 06:05 PM 2/4/2004 -0800, you wrote: >Subject: [FlyRotary] Re: air flow, induction air scoop > > > >I don't understand how a 13B can flow 277.77 cu ft/min at 6000rpm, while a >20B flows 275 cu ft. min.(Al's numbers), unless the 275 cu ft figure is >for 4000rpm instead of 6000 rpm. Using Ed's formula, I get 416.67 cu >ft/min at 6000rpm, or 31.66 lbs/minute. Which number is correct? > >Mark S. > > >Mark; > >I guess you didn t read the intervening postings where I admitted I had >made a mistake. Apparently I computed for 2 rotors instead of three. > > > >Al > > Al, No, I didn't see those later postings. I guess my mail server was running kinda slow yesterday. I'm wasn't trying to make anyone look bad, its just that I have a 20b and had calculated much higher numbers. After reading the first post, it got me to thinking I had screwed up somewhere. I'm using a 100mm tb. Mark S. --=====================_54871000==.ALT Content-Type: text/html; charset="us-ascii" At 06:05 PM 2/4/2004 -0800, you wrote:

Subject: [FlyRotary] Re: air flow, induction air scoop

I don't understand how a 13B can flow 277.77 cu ft/min at 6000rpm, while a 20B flows 275 cu ft. min.(Al's numbers), unless the 275 cu ft figure is for 4000rpm instead of 6000 rpm. Using Ed's formula, I get 416.67 cu ft/min at 6000rpm, or 31.66 lbs/minute. Which number is correct?

Mark S.

Mark;

I guess you didn t read the intervening postings where I admitted I had made a mistake. Apparently I computed for 2 rotors instead of three.

Al

Al,
No, I didn't see those later postings. I guess my mail server was running kinda slow yesterday. I'm wasn't trying to make anyone look bad, its just that I have a 20b and had calculated much higher numbers. After reading the first post, it got me to thinking I had screwed up somewhere. I'm using a 100mm tb.

Mark S. --=====================_54871000==.ALT--