Mailing List flyrotary@lancaironline.net Message #5628
From: Ed Anderson <eanderson@carolina.rr.com>
Subject: Re: [FlyRotary] air flow
Date: Fri, 30 Jan 2004 22:31:29 -0500
To: Rotary motors in aircraft <flyrotary@lancaironline.net>
Here is a formula   80 CID * RPM/1728.  Example for 6000 rpm,  80*6000
rpm/1728 = 277.77 Cubic Feet of air per minute.  A cubic foot of air (at sea
level standard day) is approx 0.076 lbm/cubic foot   so 277.77*0.076 = 21.11
lbm/min air mass at 6000 rpm .  Just change the rpm to what ever value you
want.  Also note the weight of air of course decreases with altitude so
277.77 CFM provides 21.11 lbm/minute at sea level but less at altitude.

Note this assumes 100 % Volumetric efficiency.


Ed Anderson
RV-6A N494BW Rotary Powered
Matthews, NC
----- Original Message -----
From: "Ernest Christley" <echristley@nc.rr.com>
To: "Rotary motors in aircraft" <flyrotary@lancaironline.net>
Sent: Friday, January 30, 2004 7:55 PM
Subject: [FlyRotary] air flow


> How do you compute the amount of airflow through the rotary in pounds
> per minute?
>
>
>
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