Return-Path: Received: from [24.25.9.101] (HELO ms-smtp-02-eri0.southeast.rr.com) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP id 2958817 for flyrotary@lancaironline.net; Fri, 30 Jan 2004 22:31:38 -0500 Received: from edward (clt78-020.carolina.rr.com [24.93.78.20]) by ms-smtp-02-eri0.southeast.rr.com (8.12.10/8.12.7) with SMTP id i0V3VWq3007341 for ; Fri, 30 Jan 2004 22:31:32 -0500 (EST) Message-ID: <003601c3e7aa$b70090b0$2402a8c0@edward> From: "Ed Anderson" To: "Rotary motors in aircraft" References: Subject: Re: [FlyRotary] air flow Date: Fri, 30 Jan 2004 22:31:29 -0500 MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1158 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 X-Virus-Scanned: Symantec AntiVirus Scan Engine Here is a formula 80 CID * RPM/1728. Example for 6000 rpm, 80*6000 rpm/1728 = 277.77 Cubic Feet of air per minute. A cubic foot of air (at sea level standard day) is approx 0.076 lbm/cubic foot so 277.77*0.076 = 21.11 lbm/min air mass at 6000 rpm . Just change the rpm to what ever value you want. Also note the weight of air of course decreases with altitude so 277.77 CFM provides 21.11 lbm/minute at sea level but less at altitude. Note this assumes 100 % Volumetric efficiency. Ed Anderson RV-6A N494BW Rotary Powered Matthews, NC ----- Original Message ----- From: "Ernest Christley" To: "Rotary motors in aircraft" Sent: Friday, January 30, 2004 7:55 PM Subject: [FlyRotary] air flow > How do you compute the amount of airflow through the rotary in pounds > per minute? > > > > -- > http://www.ernest.isa-geek.org/ > "Ignorance is mankinds normal state, > alleviated by information and experience." > Veeduber > > > >> Homepage: http://www.flyrotary.com/ > >> Archive: http://lancaironline.net/lists/flyrotary/List.html