Return-Path: Received: from fed1mtao04.cox.net ([68.6.19.241] verified) by logan.com (CommuniGate Pro SMTP 4.1.8) with ESMTP id 2958732 for flyrotary@lancaironline.net; Fri, 30 Jan 2004 21:46:34 -0500 Received: from BigAl ([68.107.116.221]) by fed1mtao04.cox.net (InterMail vM.5.01.06.05 201-253-122-130-105-20030824) with ESMTP id <20040131024634.OIQX29509.fed1mtao04.cox.net@BigAl> for ; Fri, 30 Jan 2004 21:46:34 -0500 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] air flow Date: Fri, 30 Jan 2004 18:46:35 -0800 Message-ID: <003c01c3e7a4$71369080$6400a8c0@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_003D_01C3E761.63135080" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.4024 In-reply-to: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 Importance: Normal This is a multi-part message in MIME format. ------=_NextPart_000_003D_01C3E761.63135080 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit Subject: [FlyRotary] air flow How do you compute the amount of airflow through the rotary in pounds per minute? According to my notes, I computed 7.8 x 106 cc/min intake air for a 3-rotor at 6000 rpm. That's 275 cfm. Two-thirds of that for a 2-rotor. You can do the conversion to lbs. I don't have the details, but my notes indicate I had come up with 3.9 liters for 3 revolutions of the output shaft. Al ------=_NextPart_000_003D_01C3E761.63135080 Content-Type: text/html; charset="US-ASCII" Content-Transfer-Encoding: quoted-printable

Subject: [FlyRotary] air flow

 

How do you compute the amount of airflow through the rotary in pounds =

per minute?

 

According to my notes, I computed 7.8 x = 106 cc/min intake air for a 3-rotor at 6000 rpm.  That’s 275 = cfm.  Two-thirds of that for a 2-rotor. You can do the conversion to = lbs.

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I don’t = have the details, but my notes indicate I had come up with 3.9 liters for 3 = revolutions of the output shaft.

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Al

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