Thomas, you are correct in that you would
like to decrease the air velocity through your core to minimum possible consistent
with adequate cooling because that (for one thing) reduces your cooling
drag. As Tracy
indicated getting cooling right tends to be a combination of understanding,
testing and some luck.
Trying to figure out cooling can drive you
bonkers, what seems intuitive can turn out to be just the opposite of what you
may think. Mr. Bernoulli’s equation can offer some understanding of
what happens in a duct with airflow (but not necessarily the complete picture).
P1A1V1 = P2A2V2 where P stands for density which is essentially constant at our
airspeeds so can be left out simplifying to A1V1 =A2V2. Or the product of
area and velocity is constant through out a duct. So if Area increases,
velocity decreases, if area decreases velocity increases.
There are other non-intuitive factors, For
example in a duct
When you slow down airflow through an area
expansion
- Pressure
in a duct increases
- Temperature
increases (very small amount at our speeds)
- Slower
air will increase in temperature (due to longer exposure to the hot metal)
- Slower
air will decrease your air mass flow which you need to carry the heat away
Boundary layer separation in a duct
generally leads to poorer cooling, rapid expansion leads to boundary layer separation,
and the secret is to prevent the boundary layer separation until the last
possible moment. The closer it happens to the core the less area of the
core is adversely affected.
It’s all about compromising
conflicting factors in a cooling system. Slower air picks up more heat per unit
mass, but faster air carries away more heat per unit time. More air mass
flow cools better, higher velocity gives more air mass flow, however, higher
velocity means more cooling drag, etc.
Stick with this group, we’ve all
been there and have conquered the cooling beast – well, at least tamed it
a bit.
Ed
From: Rotary motors in aircraft
[mailto:flyrotary@lancaironline.net] On
Behalf Of Thomas Mann
Sent: Monday, December 21, 2009
4:39 PM
To: Rotary
motors in aircraft
Subject: [FlyRotary] Re: Air Flow
Question
The numbers
I’m looking at are for relation reference only so 180kt inlet speed does
not indicate the airspeed of the aircraft (for sake of argument.)
I have read that the
airspeed needs to be reduced, hence the expansion from a 16 x 3 opening to a
core frontal area of 200 sq in.) As a result of the expansion and drop in
pressure, I realize that the air that reaches the core will be cooler than the
air that enters the inlet.
From the radiator to
the exhaust I’m looking at reducing to an opening size of approximately
75 sq inches. Based on what I have read this should slow the air down
sufficiently to get it closer to a speed where it can absorb the most heat from
the core. Some of the speeds I’ve been quoted have been in the
neighborhood of 35 kts. I don’t know how accurate those numbers are.
The air is expanding
to a greater volume after it passes through the radiator and is compressed due
to the ducting which is supposed to result in enough thrust gain to cancel out 90+%
of the drag created by the scoop.
I know that a 180
> 45 is close. I don’t know if I could get away with a smaller inlet
or if a 4 to one ration is as far as I can push it.
T Mann
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