Bernie,
Here’s another formula if you want a
crosscheck:
PropTipSpeed = Sqrt (Radius2 X AngularVelocity2 + TAS2)
where:
Angular Velocity in
radians per second
TAS in feet per second
Radius in feet
PropTipSpeed will come
out in feet per second
This was taken from the Avweb site. One
of John Deakins articles that someone mentioned here a while back.
Bryan
From: Rotary motors in aircraft
[mailto:flyrotary@lancaironline.net] On
Behalf Of Berniehb7448@wmconnect.com
Sent: Tuesday, July 07, 2009 9:45
PM
To: Rotary
motors in aircraft
Subject: [FlyRotary] Re: INJECTION
OIL IN FUEL
This is what I figured out as my "formula":
Max Prop RPM & Speed of Sound
1 Mile = 5,280 Feet
Speed of Sound = 768 mph (I think this is at sea level barometric
pressure, I haven't figured out what happens with altitude.)
pi = 3.1429
6 FT (72") D (Diameter) Prop
CIRCUMFERENCE = pi X D = 3.1429 X 6 ft =
18.857 ft Circumference
1 RPM = 18.857 ft/Minute at prop tip
With 2:1 PSRU Reduction, calculate by prop RPM and Circumference:
Prop RPM 3,000 (Engine RPM 6,000) = 56,571 ft/Minute = 10.714
miles/minute = 642.84 MPH
(768 MPH - 642.84 MPH = 125.16 MPH under Speed of Sound)
Prop RPM 3,500 (Engine RPM 7,000) = 66,000 ft/Minute = 12.5 miles/minute
= 750 MPH
(768 MPH - 750 MPH = 18 MPH under Speed of Sound)
================================================
I paid enough attention in my math classes to think I've got it right.
Here's one for you: Does a cogbelt PSRU's powerlimit increase with a wider
belt? Like, for example, if a two incher can handle 150 HP, then you might need
a four inch belt to handle 300 HP. Something like that?
Here's another: One maker put an engine RPM limit on the PSRU, and I'm thinking
it has to do with the capability of the bearing at the input end. Maybe because
these bearings are sealed - they don't run in an oil bath.
Thank you, Bernie.