X-Virus-Scanned: clean according to Sophos on Logan.com X-SpamCatcher-Score: 2 [X] Return-Path: Received: from [64.12.137.3] (HELO imo-m22.mail.aol.com) by logan.com (CommuniGate Pro SMTP 5.1.6) with ESMTP id 1863691 for flyrotary@lancaironline.net; Mon, 26 Feb 2007 09:38:37 -0500 Received-SPF: pass receiver=logan.com; client-ip=64.12.137.3; envelope-from=Lehanover@aol.com Received: from Lehanover@aol.com by imo-m22.mx.aol.com (mail_out_v38_r7.6.) id q.d3a.326685b (41810) for ; Mon, 26 Feb 2007 09:37:35 -0500 (EST) From: Lehanover@aol.com Message-ID: Date: Mon, 26 Feb 2007 09:37:35 EST Subject: Re: [FlyRotary] Re: motor mount plate To: flyrotary@lancaironline.net MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="-----------------------------1172500655" X-Mailer: 9.0 Security Edition for Windows sub 5359 X-Spam-Flag: NO -------------------------------1172500655 Content-Type: text/plain; charset="US-ASCII" Content-Transfer-Encoding: 7bit In a message dated 2/25/2007 7:30:15 P.M. Eastern Standard Time, rijakits@cwpanama.net writes: As Lynn mentioned Rotaries do "interesting" things when you get that torque to high. You ARE using a psru, so the return torque is a lot higher than what the engine dishes out. The Mistral-"system" is lot more "streamlined", than your different front(rear-housing) and PSRU. It should work just fine, though depending how much power you send through... The Mistral site does not have the PSRU reduction Ratios or the RPM where they are rating the HP. All very important. For 190 HP at 6,000 RPM you need 168 foot pounds of torque. For a PSRU ratio of 2.17 (like the Ford parts) that would give you 2,764 prop RPM ( supersonic tips or close to it) And 364 foot pounds at the prop flange and into the engine mounts. For a 2.78 PSRU ratio you would see 467 foot pounds at the prop flange and into the mounts. And 2,158 prop RPM. For 230 HP at 6,000 RPM you need 201 foot pounds of torque. For a PSRU ratio of 2.17 that gives you 436 foot pounds at the flange and into the mounts. For the 2.78 ratio it would be 558 foot pounds at the flange and into the mounts. Prop RPM same as above. Still no problem. Once you get close to 500 HP, I would be thinking about taking the torque load out through the PSRU bell housing. Or through a plate between the engine and the PSRU. That 500 HP at 6000 RPM requires 437 foot pounds of torque. For the 2.17 ratio that would be 948 foot pounds at the flange and into the mounts. For the 2.78 ratio that would be 1,214 foot pounds at the flange and into the mounts. Racing Beat built a 900 HP three rotor for a Prescot Pusher. Many turbos, and probably turning above 6000 so the boost would not have to be insane. But it can be done. Lynn E. Hanover


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In a message dated 2/25/2007 7:30:15 P.M. Eastern Standard Time,=20 rijakits@cwpanama.net writes:
<= FONT=20 style=3D"BACKGROUND-COLOR: transparent" face=3DArial color=3D#000000 size= =3D2>
As Lynn mentioned Rotaries do "interestin= g"=20 things when you get that torque to high.
You ARE using a psru, so the return torqu= e is a=20 lot higher than what the engine dishes out.
The Mistral-"system" is lot more "streaml= ined",=20 than your different front(rear-housing) and PSRU.
It should work just fine, though dependin= g how=20 much power you send through...
The Mistral site does not have the PSRU reduction Ratios or the RPM whe= re=20 they are rating the HP. All very important.
 
For 190 HP at 6,000 RPM you need 168 foot pounds of torque. For a PSRU=20 ratio of 2.17
(like the Ford parts) that would give you 2,764 prop RPM ( supersonic t= ips=20 or close to it)
And 364 foot pounds at the prop flange and into the engine mounts.
 
For a 2.78 PSRU ratio you would see 467 foot pounds at the prop fl= ange=20 and into the mounts. And 2,158 prop RPM.
 
For 230 HP at 6,000 RPM you need 201 foot pounds of torque. For a PSRU=20 ratio of 2.17 that gives you 436 foot pounds at the flange and into the= =20 mounts. For the 2.78 ratio it would be 558 foot pounds at the flange an= d=20 into the mounts. Prop RPM same as above. 
 
Still no problem.
 
Once you get close to 500 HP, I would be thinking about taking the torq= ue=20 load out through the PSRU bell housing. Or through a plate between the engin= e=20 and the PSRU.
 
That 500 HP at 6000 RPM requires 437 foot pounds of torque. For th= e=20 2.17 ratio that would be 948 foot pounds at the flange and into the mounts.=20= For=20 the 2.78 ratio that would be
1,214 foot pounds at the flange and into the mounts.
 
Racing Beat built a 900 HP three rotor for a Prescot Pusher. Many turbo= s,=20 and probably turning above 6000 so the boost would not have to be insane. Bu= t it=20 can be done.  
 
 
Lynn E. Hanover



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