Mailing List flyrotary@lancaironline.net Message #29013
From: george lendich <lendich@optusnet.com.au>
Subject: Re: [FlyRotary] Re: Fw: [FlyRotary] Re: Dodge vs Ford
Date: Sat, 7 Jan 2006 18:53:33 +1000
To: Rotary motors in aircraft <flyrotary@lancaironline.net>
Re: [FlyRotary] Fw: [FlyRotary] Re: Dodge vs Ford
Ken,
Thanks for that info:
62/28 = 2.21+1 =3.21 - your correct, yet again!
Sun gear 28 against 42 that's interesting, 1.5 times the size teeth, that does make it stronger.
 
Point taken on the planet gear speed as well.
 
I think the bigger teeth will give less contact area, but the greater load transfer is compensated with the increased sized teeth.
 
Thanks Ken - I hope I helped eliminate the confusion!
George
 
   The tooth count for the dodge is 62 on ring 28 on the sun and 17 on the planets.
  Comparing the C-6 gears that are used in the 2.17 and 3.17 ratio to the Dodge 3.21 ratio the Dodge gears have much bigger teeth, the sun gears are the same outside diameter but the C-6 has teeth and the Dodge has 28 teeth, this is do to the larger teeth on the Dodge.
  Also the ring gears have the same inside diameter but the C-6 has 74 teeth and the dodge has 62 teeth do to the larger teeth on the Dodge.
  The surface speed remains about the same but the teeth are bigger, sounds stronger to me.
  I have built off road race car transmissions for years and although manual not stick and always the gears with bigger teeth were always stronger.
  Another thing that I noticed when I was looking at gears at the tranny shop is that the C-6 set that gives 2.85 ratio has a bigger sun gear and the planet gears were real small do to the larger sun gear so that would raise the planet gear rpm.
  Here is a shot of both gears side by side, its clear to see the difference.
  Ken Welter




 
Ken,
Some additional info!
 
I look at the planetary as I look at a external toothed gear engaged to a drive gear.
The smaller drive gear has to travel ( with the E4D)  2.85 times further than the larger gear ( the larger gear has 2.85 times additional teeth).
 
The planetary gears ( in my mind ) merely transfers the loads. Their not involved with varying the Ratio!
 
No matter how it's used in a Vehicle/ Truck, we will use it the same as we use the other planetaries, so the assessment is the same as the other planetaries.
 
So I'm figuring that the ring gear must be about 84 for the ring gear and about 38 for the sun gear e.g.  84/ 38 = 2.21 +1 =3.21
 
If you can give me the tooth count we can evaluate from there - no pressure and no confusion.
George ( down under)
 
 
 
 
Ken,
The ratio is ring gear tooth (numbers) divided by sun gear teeth( numbers).
If  drive is taken out of the planet (turning RH) = A divided by B = 2.21+ 1 = 3.21
If drive is taken out of the ring gear ( turning LH) = A divided by B = 3.21
 
EG the E4D is 78 toothed Ring gear divided by the 42 toothed sun gear =1.85:1+1 = 2.85:1
and the 2.17  is a LH turning planetary with ring gear held can't remember the tooth count.
It doesn't matter 'what drives what' in the Truck - just count the teeth.
George ( down under)
 


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