Well guys here you all go getting
tangled up in you analytical undies.
I keep trying to tell you to stop
getting confused about the hardware and just pretend it does not even
exist.
A fixed amount of air and fuel goes
in.
It is compressed.
It is ignited.
It is expanded
It is exhausted
Now the question is for this one
packet what is the maximum amount that can be ingested at atmospheric
pressure.
.65 liters per chamber.
what constitutes a chamber?
A rotor face.
How many are there?
How long does it take to run all the
little packets through one complete cycle?
The true thermodynamic eqivalent is a 3.9L
6 cyl motor spining at 1/3 eshaft speed.
You may choose a 1.3 L 6 cylinder
spining 3 times as fast if you like and get the same numbers.
You may also choose a 2.6 L spining
2/3 as fast
Or you may play any game of two
cycle four cycle six cycle etc.
Or you could just make up some
arbitrary way to make the numbers work out.
You could also say that 302 cubic
inch engine is actually a 604 cubic inch engine if spun twice as fast
and choose to calculate displacement via the cam drive.
The point is the only thing that
matters when comparing oranges and oranges is that one little chamber
or single cylinder. Not half a cylinder or 2/3 of cylinder or chamber.
The working fluid is the key-not the
hardware.....I promise.
I still maintain that it doesn't
make a hill of beans of difference. The mental exercise beats watching
Oprah, however.
Monty