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Message-ID: <1c23473f0510171754la781de6m35151d99b0e809f5@mail.gmail.com>
Date: Mon, 17 Oct 2005 17:54:00 -0700
From: David Leonard <wdleonard@gmail.com>
To: Rotary motors in aircraft <flyrotary@lancaironline.net>
Subject: Re: [FlyRotary] flyrotary Displacement
In-Reply-To: <list-771510@logan.com>
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  what constitutes a chamber?
>

 A rotor face.
>
 I disagree, but this is irrelevant.

   The true *thermodynamic* eqivalent is a 3.9L 6 cyl motor spining at 1/3
> eshaft speed.
>
 no, 2/3 e-shaft speed

  You may choose a 1.3 L 6 cylinder spining 3 times as fast if you like and
> get the same numbers.
>
 no, twice e-shaft speed.

  You may also choose a 2.6 L spining 2/3 as fast
>
 No, a 2.6 L spinning AT e-shaft speed. That is why I claim that the rotary
is a 2.6 L equavelent. I don't understand this "pretend that the RPM is
something different".

--
Dave Leonard
Turbo Rotary RV-6 N4VY
http://members.aol.com/_ht_a/rotaryroster/index.html
http://members.aol.com/_ht_a/vp4skydoc/index.html

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<br><br>
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div><font face=3D"Arial" size=3D"2"></font></div>
<div><font face=3D"Arial" size=3D"2"></font>&nbsp;</div>
<div><font face=3D"Arial" size=3D"2">what constitutes a chamber?</font></di=
v>
<div>&nbsp;</div></blockquote>
<div><br>&nbsp;</div>
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div><font face=3D"Arial" size=3D"2">A rotor face.</font></div></blockquote=
>
<div>&nbsp;</div>
<div>I disagree, but this is irrelevant.</div>
<div><br>&nbsp;</div>
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div>
<div><font face=3D"Arial" size=3D"2"></font></div><font face=3D"Arial" size=
=3D"2"></font><font size=3D"2"></font>&nbsp;</div>
<div><font face=3D"Arial" size=3D"2">The true <strong><u><font color=3D"#ff=
0000">thermodynamic</font></u></strong> eqivalent is a 3.9L 6 cyl motor spi=
ning at 1/3 eshaft speed.</font></div></blockquote>
<div>&nbsp;</div>
<div>no, 2/3 e-shaft speed</div><br>
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div>&nbsp;</div>
<div><font face=3D"Arial" size=3D"2">You may choose a 1.3 L 6 cylinder spin=
ing 3 times as fast if you like and get the same numbers.</font></div></blo=
ckquote>
<div>&nbsp;</div>
<div>no, twice e-shaft speed.</div><br>
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<div>&nbsp;</div>
<div><font face=3D"Arial" size=3D"2">You may also choose a 2.6 L spining 2/=
3 as fast </font></div></blockquote>
<div>&nbsp;</div>
<div>No, a 2.6 L spinning AT e-shaft speed.&nbsp; That is why I claim that =
the rotary is a 2.6 L equavelent.&nbsp; I don't understand this &quot;prete=
nd that the RPM is something different&quot;.</div>
<p>-- <br>Dave Leonard<br>Turbo Rotary RV-6 N4VY<br><a href=3D"http://membe=
rs.aol.com/_ht_a/rotaryroster/index.html">http://members.aol.com/_ht_a/rota=
ryroster/index.html</a><br><a href=3D"http://members.aol.com/_ht_a/vp4skydo=
c/index.html">
http://members.aol.com/_ht_a/vp4skydoc/index.html</a> </p>

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