Well guys here you all go getting tangled up in you analytical undies.

 

I keep trying to tell you to stop getting confused about the hardware and just pretend it does not even exist.

 

A fixed amount of air and fuel goes in.

 

It is compressed.

 

It is ignited.

 

It is expanded

 

It is exhausted

 

 

Now the question is for this one packet what is the maximum amount that can be ingested at atmospheric pressure.

 

.65 liters per chamber.

 

what constitutes a chamber?

 

A rotor face.

 

How many are there?

 

How long does it take to run all the little packets through one complete cycle?

 

The true thermodynamic eqivalent is a 3.9L 6 cyl motor spining at 1/3 eshaft speed.

 

You may choose a 1.3 L 6 cylinder spining 3 times as fast if you like and get the same numbers.

 

You may also choose a 2.6 L spining 2/3 as fast

 

Or you may play any game of two cycle four cycle six cycle etc.

 

Or you could just make up some arbitrary way to make the numbers work out.

 

You could also say that 302 cubic inch engine is actually a 604 cubic inch engine if spun twice as fast and choose to calculate displacement via the cam drive.

 

The point is the only thing that matters when comparing oranges and oranges is that one little chamber or single cylinder. Not half a cylinder or 2/3 of cylinder or chamber.

 

The working fluid is the key-not the hardware.....I promise.

 

 

I still maintain that it doesn't make a hill of beans of difference. The mental exercise beats watching Oprah, however.

 

 

Monty