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From: Lehanover@aol.com
Message-ID: <141.3f38ed17.2f3cea58@aol.com>
Date: Thu, 10 Feb 2005 11:48:24 EST
Subject: Re: [FlyRotary] Rotary AirFlow Equation? Help?
To: flyrotary@lancaironline.net
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In a message dated 2/10/2005 10:11:02 AM Central Standard Time, 
eanderson@carolina.rr.com writes:

<< I would greatly appreciate any assistance in helping me understand where I 
have gone wrong in logic or math.  Please don't just quote an authority or 
formula - explain it and show me your calculations on how you got there.  Its 
things like this that keep me awake at night {:>).
 
 Help Meee..!   
 
 Thanks
 
 Ed
  >>

The Sports Car Club of America says my 12A has a displacement of 2292ccs, or 
twice the 1147CCs on the data plate. The thinking is that the engine displays 
or cycles through an example of its total displacement with one revolution, 
that it is at least similar to a 2 cylinder two cycle engine. So to compare it 
to a 4 cycle engine, they turn it over twice, as is required for a 4 stroke 
engine to display its total displacement.  

At 6,500 RPM, my Bridgeport 12A had 139.6 foot pounds of torque and 173.3 HP 
at 12.13 A/F and .666 BSFC. This is with a Weber two choke IDF carb with two 
36MM chokes.

Max power is at 9,400 RPM 136.7 foot pounds of torque and 244.9 HP at 13.8 
A/F and .645 BSFC.

The engine is not built to operate at 6,500 but 7,500 to 9,600. We just pass 
through 6,500 leaving the pits, and then again after the race.

Lynn E. Hanover