Return-Path: Received: from fed1rmmtao03.cox.net ([68.230.241.36] verified) by logan.com (CommuniGate Pro SMTP 4.2.8) with ESMTP id 607985 for flyrotary@lancaironline.net; Sat, 15 Jan 2005 02:06:19 -0500 Received-SPF: none receiver=logan.com; client-ip=68.230.241.36; envelope-from=ALVentures@cox.net Received: from BigAl ([68.7.14.39]) by fed1rmmtao03.cox.net (InterMail vM.6.01.04.00 201-2131-117-20041022) with ESMTP id <20050115070547.EYCI8778.fed1rmmtao03.cox.net@BigAl> for ; Sat, 15 Jan 2005 02:05:47 -0500 From: "Al Gietzen" To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: water cooled matrix in oil pan Date: Fri, 14 Jan 2005 23:05:52 -0800 Message-ID: <000001c4fad0$a68d82d0$6400a8c0@BigAl> MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0001_01C4FA8D.986A42D0" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 This is a multi-part message in MIME format. ------=_NextPart_000_0001_01C4FA8D.986A42D0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Subject: [FlyRotary] Re: water cooled matrix in oil pan =20 <...oil moves in the channels of the oil cooler at about 20 ft/min ...=20 oil entered the pan at one end and traversed across it might be moving=20 about =BD ft/min ...> =20 20 fpm through the cooler seems really slow. What is the oil pump output = volume? I'd have thought something on the order of 10 gpm or so. 20 fpm=20 through a foot long oil cooler that holds a quart of oil is only 5 gpm=20 output from the pump. Is that right? =20 Trying to do the math ... Jim S. =20 I guess my 30 second calculation is wrong =96 too low by a factor of 12 = (1728 cu. in. in a cu. ft.; not 144) so it should be 240 ft/min, 4 ft/sec = (that=92s more like it). It=92s a rough estimate for 12 gpm and about a square = inch of passage area. Same factor for the movement in the pan =96 about 6 = ft/min. =20 Thanks for pointing that out. =20 Al ------=_NextPart_000_0001_01C4FA8D.986A42D0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

Subject: [FlyRotary] Re: water cooled matrix in oil pan

<...oil moves in the channels of the oil cooler at about 20 ft/min ... =

oil entered the pan at one end and traversed across it might be moving =

about =BD ft/min ...>

20 fpm through the cooler seems really slow. What is the oil pump output =

volume? I'd have thought something on the order of 10 gpm or so. 20 fpm =

through a foot long oil cooler that holds a quart of oil is only 5 gpm =

output from the pump. Is that right?

Trying to do the math ... Jim S.

I guess my 30 second calculation is wrong – = too low by a factor of 12 (1728 cu. in. in a cu. ft.; not 144) so it should be = 240 ft/min, 4 ft/sec (that’s more like it).=A0 It’s a rough estimate for = 12 gpm and about a square inch of passage area.=A0 Same factor for the movement = in the pan – about 6 ft/min.

Thanks for pointing that out.

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