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jbker@juno.com wrote:
Ed A wrote:
For you sound experts, I presume if a 3DB increase represents a perceived doubling of loudness does that mean a 10 DB decrease represents an approx 3 fold decrease in perceived loudness??
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Do not claim to be a noise expert, but did some measurements on the P&W jets over the years. If you cut the noise 10 Db, I think that is 1/8 the perceived noise (1/2X1/2X1/2= 1/8) Bernie
1/8 would be -9dB. 1/10 would be -10dB.
dB = 10 * log(ratio)
10 * log(1/10) = 10 * -0,1 = -10dB.
Had enough?
Finn (need to do the airplane annual before I can fly it again)
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