Return-Path: Sender: (Marvin Kaye) To: flyrotary Date: Mon, 17 Mar 2003 08:30:18 -0500 Message-ID: X-Original-Return-Path: Received: from cpimssmtpu11.email.msn.com ([207.46.181.86] verified) by logan.com (CommuniGate Pro SMTP 4.0.6) with ESMTP id 2054572 for flyrotary@lancaironline.net; Sun, 16 Mar 2003 14:58:06 -0500 X-Originating-IP: 68.7.218.110 Received: from BigAl ([68.7.218.110]) by cpimssmtpu11.email.msn.com with Microsoft SMTPSVC(5.0.2195.4617); Sun, 16 Mar 2003 11:56:48 -0800 Reply-To: From: "Al Gietzen" X-Original-To: "'Rotary motors in aircraft'" Subject: RE: [FlyRotary] Re: Fuel Injection X-Original-Date: Sun, 16 Mar 2003 11:57:16 -0800 Organization: ALVentures X-Original-Message-ID: <000001c2ebf6$41f62dd0$6400a8c0@BigAl> MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.4024 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 X-Original-Return-Path: alventures@email.msn.com X-OriginalArrivalTime: 16 Mar 2003 19:56:48.0511 (UTC) FILETIME=[2DF1F8F0:01C2EBF6] The amount of fuel returning to the sump is the flow rate from the pump minus the amount the engine is burning. So if the pump is putting out 35 gph, and the engine is burning 15 gph you've got 25 gph going back to the sump. Oops; I'm embarrassed. I'm not really so mathematically challenged that I can't subtract. Let's just call it a typo. Let's see - 35 minus 15 is ah . . . ah . . well; I don't think it's 25. Al